Answer:
25.5 and 37.5
Step-by-step explanation:
x+y=63
x-y = 12 then x = 12 + y sub this into the first equation
(12+y) + y = 63
12 + 2y = 63
2y = 51
y = 25.5 then x = 37.5
Answer:

<h3><u>m=18</u> is the right answer.</h3>
It’s 22/3 I think so that’s the answer
<h3>Answer:</h3>
- ABDC = 6 in²
- AABD = 8 in²
- AABC = 14 in²
<h3>Explanation:</h3>
A diagram can be helpful.
When triangles have the same altitude, their areas are proportional to their base lengths.
The altitude from D to line BC is the same for triangles BDC and EDC. The base lengths of these triangles have the ratio ...
... BC : EC = (1+5) : 5 = 6 : 5
so ABDC will be 6/5 times AEDC.
... ABDC = (6/5)×(5 in²)
... ABDC = 6 in²
_____
The altitude from B to line AC is the same for triangles BDC and BDA, so their areas are proportional to their base lengths. That is ...
... AABD : ABDC = AD : DC = 4 : 3
so AABD will be 4/3 times ABDC.
... AABD = (4/3)×(6 in²)
... AABD = 8 in²
_____
Of course, AABC is the sum of the areas of the triangles that make it up:
... AABC = AABD + ABDC = 8 in² + 6 in²
... AABC = 14 in²
Answer:
a

b

Step-by-step explanation:
From the question we are told that
The proportion that has outstanding balance is p = 0.20
The sample size is n = 15
Given that the properties of the binomial distribution apply, for a randomly selected number(X) of credit card

Generally the probability of finding 4 customers in a sample of 15 who have "maxed out" their credit cards is mathematically represented as

=> 
Here C stand for combination
=>
Generally the probability that 4 or fewer customers in the sample will have balances at the limit of the credit card is mathematically represented as
![P(X \le 4) = [ ^{15}C_0 * (0.20)^0 * (1 - 0.20)^{15-0}]+[ ^{15}C_1 * (0.20)^1 * (1 - 0.20)^{15-1}]+\cdots+[ ^{15}C_4 * (0.20)^4 * (1 - 0.20)^{15-4}]](https://tex.z-dn.net/?f=P%28X%20%5Cle%204%29%20%3D%20%20%5B%20%5E%7B15%7DC_0%20%2A%20%280.20%29%5E0%20%2A%20%281%20-%200.20%29%5E%7B15-0%7D%5D%2B%5B%20%5E%7B15%7DC_1%20%2A%20%280.20%29%5E1%20%2A%20%281%20-%200.20%29%5E%7B15-1%7D%5D%2B%5Ccdots%2B%5B%20%5E%7B15%7DC_4%20%2A%20%280.20%29%5E4%20%2A%20%281%20-%200.20%29%5E%7B15-4%7D%5D)
=> 