3 years ago

Help...anyone plzzzzzzzzz

Mathematics

2 answers:

earnstyle [38]3 years ago

7 0

It needs to be at least conjunction because I'm dumb and don't how to do math cause I'm dumb so the answer is -45 (idk)

Arte-miy333 [17]3 years ago

4 0

Can you please take another picture that is closer to the diagram, it's quite blurry.

You might be interested in

In the complex number system, which of the following is equal to

pogonyaev

Answer:

C) $122+154i$

Step-by-step explanation:

$(14-2i)(7+12i)\\\\(14)(7)+(14)(12i)+(-2i)(7)+(-2i)(12i)\\\\98+168i-14i-24i^2\\\\98+154i-24(-1)\\\\98+154i+24\\\\122+154i$

Therefore, C is correct. Recall that $i^2=-1$

3 0

2 years ago

Read 2 more answers

I’m on a test so I need help

sladkih [1.3K]

The answer is 2 y2 -9

4 0

3 years ago

5-2.1=? 5-2.17=? 5-2 7/8 solve make sure to re-check your self before answering or no forty points

frozen [14]

Answer: 5-2.1= 2.9

5-2.17= 2.83

5-2 7/8= 2.125

6 0

3 years ago

Find the product.<br><br> (−x−3)(2x2+5x+8)=

harina [27]

$( - x - 3)(2 {x}^{2} + 5x + 8) = \\ = - 2 {x}^{3} - 5 {x}^{2} - 8x - 6 {x}^{2} - 15x - 24 = \\ = - 2 {x}^{3} - 11 {x}^{2} - 23x - 24$

3 0

3 years ago

The velocity v of the flow of blood at a distance r from the central axis of an artery of radius R is given below, where k is th

andrew11 [14]

The average rate of blood flow is given by

$\displaystyle\frac1{R-0}\int_0^Rv(r)\,\mathrm dr=\frac kR\int_0^R(R^2-r^2)\,\mathrm dr$
$=\dfrac kR\left(R^2r-\dfrac13r^3\right)\bigg|_{r=0}^{r=R}$
$=\dfrac kR\left(R^3-\dfrac13R^3\right)$
$=\dfrac{2kR^2}3$

3 0

3 years ago