Answer:
Explanation:
I will show my thinking using words and numbers.
The fact that when the camels walked in rows of 2 one walked alone means tha the number of camels divided by 2 leaves a remainder of 1. Also, that means that if you subtract 1 from the number of camels, the new number is a multiple of 2. This is:
- The number of camels less 1 is a multiple of 2.
With the same reasoning, you obtain:
- The number of camels less 1 is a multiple of 3.
- The number of camels less 1 is a multiple of 4.
- The number of camels less 1 is a multiple of 5.
Now, the numbers of camels less 1 is a multiple of 2, 3, 4, and 5. Now, let's search the first (least) common multiple of 2, 3, 4, and 5.
For that, you have to factor each number into its prime factors:
The least common multiple is the product of the common and uncommon factors, each raised to its highest power: 2² × 3 × 5 = 60.
Remember that 60 is the number of camels less 1, thus the number of camels is 60 + 1 = 61.
The next common multiple is 2 × 60 = 120, which exceeds 100 thus the only possible value is the one determined above.
Now you can prove that 61 meets the conditions:
- 61 ÷ 2 = 30, plus one (remainder): means that 60 camels walked in 30 rows of 2 and one walked alone.
- 61 ÷ 3 = 20, plus one: 60 camels walked in 20 rows of 3 and one walked alone.
- 61 ÷ 4 = 15, plus one: 60 camels walked in 14 rows of 4 and one walked alone.
- 61 ÷ 5 = 12, plus one: 60 camels walked in 12 rows of 5 and one walked alone.
Answer:
she spent $7.45 on each rope at the sale price. The original price would have been $8.70
Step-by-step explanation:
What’s the question to go with the 10 numbers.
This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by <span>33</span> gives the next term. In other words, <span><span><span>an</span>=<span>a1</span>⋅<span>r<span>n−1</span></span></span><span><span>an</span>=<span>a1</span>⋅<span>r<span>n-1</span></span></span></span><span>.</span>
