Hello,

$u_{1} =4\\
 u_{2} =4*q\\
 u_{3} =4*q^2\\
...\\

 u_{9} =4*q^8\\\\
==\textgreater\ 4*q^8=1024\\
==\textgreater\ q^8=256\\
==\textgreater\ q=2\mbox{( and there is a problem in the question) } \ or \ q=-2\\
if\ q=2 \ then\ \sum_{i=0}^{8}\ 4*(2)^i= 4*\dfrac{1-2^9}{1-2} =2044\\

if \ q=-2 \ then\ \sum_{i=0}^{8}\ 4*(-2)^i= 4*\dfrac{1-(-2)^9}{1+2} =684\\



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Answer B (but see the problem)

7 0

3 years ago

Read 2 more answers

Find the m TFS. Answer choices are: 12 degrees 76 degrees 64 degrees 52 degrees

goblinko [34]

It’s 52 because there are two sides with 64 degrees (the bottom two sides) and you add those to sides together and subtract your combine angle of the bottom 2 sides by 180 degrees which is the degree of all triangles combine and get 52

4 0

3 years ago