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Leni [432]
3 years ago
15

Tom drove 130 Miles at the speed of 65 mph, and then 200 more miles at the speed of 30 mph. What was his average speed for the e

ntire trip?
Mathematics
1 answer:
ch4aika [34]3 years ago
7 0
47.5 mph- because 30+65 equals 95 and 95 divided by 2 is 47.5
You might be interested in
Which table of ordered pairs represents a proportional relationship?
gladu [14]

The table that represents a proportional relationship is:

x = -1, -3, -5

y = 1, 3, 5

<h3>Which table represents a proportional relation?</h3>

A proportional relationship is written as:

y = k*x

Where k is the constant of proportionality.

Notice that for equidistant increases in x, we should have equidistant increases on y. Also, proportional relations always have the point (0, 0)

Then the table that represents a proportional relationship is:

x = -1, -3, -5

y = 1, 3, 5

Where the proportional relation is:

y = (-1)*x

When x = -1

y = (-1)*(-1) = 1

When x = -3

y = (-1)*-3 = 3

When x = -5

y = (-1)*(-5) = 5

So the correct option is the second one.

If you want to learn more about proportional relationships:

brainly.com/question/12242745

#SPJ1

6 0
2 years ago
Bob has a standard deck of playing cards. If he randomly draws a J, K, 2, and 2, what is the probability that the next card he d
nlexa [21]

Answer:

The correct answer has already been given (twice). I'd like to present two solutions that expand on (and explain more completely) the reasoning of the ones already given.


One is using the hypergeometric distribution, which is meant exactly for the type of problem you describe (sampling without replacement):


P(X=k)=(Kk)(N−Kn−k)(Nn)


where N is the total number of cards in the deck, K is the total number of ace cards in the deck, k is the number of ace cards you intend to select, and n is the number of cards overall that you intend to select.


P(X=2)=(42)(480)(522)


P(X=2)=61326=1221


In essence, this would give you the number of possible combinations of drawing two of the four ace cards in the deck (6, already enumerated by Ravish) over the number of possible combinations of drawing any two cards out of the 52 in the deck (1326). This is the way Ravish chose to solve the problem.


Another way is using simple probabilities and combinations:


P(X=2)=(4C1∗152)∗(3C1∗151)


P(X=2)=452∗351=1221


The chance of picking an ace for the first time (same as the chance of picking any card for the first time) is 1/52, multiplied by the number of ways you can pick one of the four aces in the deck, 4C1. This probability is multiplied by the probability of picking a card for the second time (1/51) times the number of ways to get one of the three remaining aces (3C1). This is the way Larry chose to solve the this.

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Please help!! <br><br> determine an equation<br><br> ( ax^3 * bx^2 + cx + d ) <br><br> for the data.
Aliun [14]

Answer:

abx^5+cx+d

Step-by-step explanation:

This is the expression simplified

5 0
3 years ago
Can someone help please
Over [174]

Answer:

She is wrong. Only expression A and, expression C are equal.

Plz thank and rate brainliest.


8 0
3 years ago
What is 12 times 2 times 5 plus 2​
Vsevolod [243]

Answer:

122

Step-by-step explanation:

12 times 2 times 5 plus 2 gets rewritten as

(12)(2)(5) + 2

Follow PEMDAS and do multiplication first.  From left to right...

 24(5) + 2                      {   (12)(2) = 24   }

   120 + 2                        {  (24)(5) = 120   }

  122                               {   120 + 2 = 122   }

8 0
2 years ago
Read 2 more answers
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