3 years ago

PLEASE HELP SOLVE THE PHOTO

Mathematics

1 answer:

Svet_ta [14]3 years ago

8 0

Answer:

a 7

Step-by-step explanation:

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Please help!

tensa zangetsu [6.8K]

If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
-2 = 9a/4 + k
Substitute (2, -4): -4 = a(-1/2)^2 + k
-4 = a/4 + k
Subtracting: 2 = 2a, so a = 1. Substituting back gives k = -17/4.
So the equation is y = (x - 5/2)^2 - 17/4
Expanding: y = x^2 - 5x + 25/4 - 17/4
y = x^2 - 5x + 2 (This is the standard form.)

5 0

2 years ago

How whorls I slice this and what’s the answer?

Olenka [21]

Here is a graph. When you use a graphing calculator, it isn't always necessary to solve for y.

Note different colors are used for the different problems. Problem 2 has a dashed line, as described by "Remember, ...".