Find the value of p for which x = -2, y = -1 is a solution of linear equation 5x + 2py = 2p.

1 answer:

8 0

I think p=4
How I solved it:
5(-2)+2p+2(-1)=2p
-10+2p+-2=2p So cross out last
-2p -2p 2p:)
= -10+2p+-2
+10 +10 Cross out the 10
= 2p=8
= divide both sides by 2p
= 2p/2= 8/2
= cross out the 2.
= which leaves
= p=4 we get 4 because we divide 8 to 2:)

I don’t know if I’m right but yea...

You might be interested in

Beatrice contributes 18% of her $59,800 annual salary to her 401(k) plan. What is her pre-tax income?

nalin [4]

<span>B. $49,036 hope helps APEX </span>

7 0

3 years ago

Read 2 more answers

Evaluate 82 - 2^3 x5

Anettt [7]

I think the answer is 42.

6 0

2 years ago

Read 2 more answers

What is the next letter b a d e h g k

aivan3 [116]

Abcdefghijklmnopqrstuvwxyz

ok

b to a
goes back 1 letter

then b to d
skips 3 letters forward

then d to e
1 forward

e to h
skips 3 forward

h to g
goes 1 back

g to k
goes 3 forward

pattern seems to be
1back, 3 forward, 1 forward, 3 forward, repeat
so we are at 3 forward after than 1 back, so the next one is 1 forward

1 forward from k is l

the next letter is L

8 0

3 years ago

Given the differential Equation y'+2y=2e^x ;solve this equation using the integration factor; solve for y to get the general sol

SCORPION-xisa [38]

$y'+2y=2e^x\Longrightarrow y'=2e^x-2y$

If $f'(x)=g(x)$ then $y=\int{g(x)dx}$

So we extract,

$y=\int{2e^x-2x}dx$

Which becomes,

$y=2e^x-x^2+C$

Hope this helps.

r3t40

5 0

2 years ago

Researchers studied symptom distress and palliative care designation among a sample of 710 hospitalized patients. Controlling fo

N76 [4]

Answer:

A. Men had less distress from nausea on average than women but we can not determine if this is a significant difference.

Step-by-step explanation:

Working based on the information given, the mean values of each group with with men having an average score of 1.02 and women have an average of 1.79 this reveals that distressing nausea on average is higher in women than in men . However, to test if there is a significant difference would be challenging as the information given isn't enough to make proceed with the test as the standard deviations of the two groups aren't given and no accompanying sample data is given.

8 0

2 years ago

Find the value of p for which x = -2, y = -1 is a solution of linear equation 5x + 2py = 2p.​

Find the value of p for which x = -2, y = -1 is a solution of linear equation 5x + 2py = 2p.