The solution would be like
this for this specific problem:
<span>V = ∫ dV </span><span>
<span>= ∫0→2 ∫
0→π/2 ∫ 0→ 2·r·sin(φ) [ r ] dzdφdr </span>
<span>= ∫0→2 ∫
0→π/2 [ r·2·r·sin(φ) - r·0 ] dφdr </span>
<span>= ∫0→2 ∫
0→π/2 [ 2·r²·sin(φ) ] dφdr </span>
<span>= ∫0→2 [
-2·r²·cos(π/2) + 2·r²·cos(0) ] dr </span>
<span>= ∫0→2 [
2·r² ] dr </span>
<span>=
(2/3)·2³ - (2/3)·0³ </span>
<span>= 16/3 </span></span>
So the volume of the
given solid is 16/3. I am hoping that these answers have satisfied
your query and it will be able to help you in your endeavors, and if you would
like, feel free to ask another question.
Answer:
a = -1.58
Step-by-step explanation:
1/3 +a+5/4 =0
1/3+5/4= -a
4+15/12 = -a
19/12 = -a
1.58= -a
1.58/-1 = -a/-1
-1.58 = a
Answer:
<h2>2.2</h2>
Step-by-step explanation:
Use the cosine law:
We have:
Substitute:
Answer:
4(x - 2)^2 + 3x – 2 + 1 = 0
Step-by-step explanation:
The equation that has a highest x-power (degree) of 2 is quadratic.
The degrees of the answer choices are ...
So, only the first answer choice is a quadratic.
Answer:
Step-by-step explanation:
Add them all together to get your answer
