Answer:
<h3>
present age of son = 10 </h3><h3>
present age of father = 40</h3>
Step-by-step explanation:
Let, present age of son be 'x'
present age of father be 'y'
y = 4x→ equation ( i )
After five years,
Son's age = x + 5
father's age = y + 5
According to Question,
![y + 5 = 3(x + 5)](https://tex.z-dn.net/?f=y%20%2B%205%20%3D%203%28x%20%2B%205%29)
Put the value of y from equation ( i )
![4x + 5 = 3(x + 5)](https://tex.z-dn.net/?f=4x%20%2B%205%20%3D%203%28x%20%2B%205%29)
Distribute 3 through the parentheses
![4x + 5 = 3x + 15](https://tex.z-dn.net/?f=4x%20%2B%205%20%3D%203x%20%2B%2015)
Move variable to L.H.S and change it's sign
Similarly, Move constant to R.H.S. and change its sign
![4x - 3x = 15 - 5](https://tex.z-dn.net/?f=4x%20-%203x%20%3D%2015%20-%205)
Collect like terms
![x = 15 - 5](https://tex.z-dn.net/?f=x%20%3D%2015%20-%205)
Calculate the difference
![x = 10](https://tex.z-dn.net/?f=x%20%3D%2010)
Now, put the value of X in equation ( i ) in order to find the present age of father
![y = 4x](https://tex.z-dn.net/?f=y%20%3D%204x)
plug the value of X
![= 4 \times 10](https://tex.z-dn.net/?f=%20%3D%204%20%5Ctimes%2010)
Calculate the product
![= 40](https://tex.z-dn.net/?f=%20%3D%2040)
Therefore,
Present age of son = 10
present age of father = 40
Hope this helps..
Best regards!!
Quarterly compounding after 5 years nets $4,133.24 in compounded interest.
As for simple interest, I made an assumption that there was a 5% per quarter interest.
20% (5yrs * 4 qtrs.) gives total interest on $2,500 in the amount of $500.
Difference is $3,633.24
Answer:
12,145
Step-by-step explanation:
If 347 cans is the max PER week, and they have 35 weeks, then all we need to do is multiply 347 times 35.
347*35 = 12,145
The max amount of cans they can collect in 35 weeks is 12,145 cans.
Answer:
3.025 x 10³ sq ft
Step-by-step explanation: