I have a link but it’s not fake
Answer C
Step-by-step explanation: lol idk
Answer:
The fourth graph.
Step-by-step explanation:
We have f(x + 1) so the x values will be increased by 1.
first value = 108 (when x = 1)
next value = 108 * 2/3 = 72 (when x = 2)
next = 72 * 2/ 3= 48 (when x = 3)
next = 48 * 2/3 = 32 (when x = 4)
She bought 4, then she bought 3 more....so she bought 7 packs
each pack contains 12 pencils..
so 7 packs each containing 12 pencils ...
7(12) = 84 total pencils <===
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719