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3 years ago

How many solutions exist for the given equation?

1 answer:

4 0

Answer: Infinitely many solutions when we graph this it comes out as one straight line also try using Desmos it helps with equations like this by graphing them for you! -Your friend, Bill Cipher

Step-by-step explanation: Have a great Valentines day <3

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Pls write answer as soon as possible

Tomtit [17]

Answer:

Step-by-step explanation:

11.-3(2x-8)=-12

-6x+24=-12

-6x=-12-24

x=-36/-6

x=6

12.4(6+2x)=0

24+8x=0

8x=0-24

x=-24/8

x=-3

13.3x+2x+6=-15

5x+6=-15

5x=-15-6

x=-21/5

14.4=-2(x+3)

4=-2x-6

4+6=-2x

10/-2=x

-5=x

15.27=46+2x-x

27=46+x

27-46=x

-19=x

7 0

3 years ago

Read 2 more answers

A triangle, ABC, has angle measures of 82', 75', and 23' and no sides equal (congruent) in length. How would this

andreev551 [17]

Answer:

No sides equal means scalene.

All angles less than 90 degrees acute triangle.

http://www.1728.org/triang.htm

Step-by-step explanation:

5 0

3 years ago

Which expression is equivalent to (3+z)6+18z

Novosadov [1.4K]

24 haha. Hahaha

Explain

4 0

3 years ago

There is a book sale at the libaray the price for each book is $4 which expression can be used to show how much money the librar

ASHA 777 [7]

4 x 289= the total cost

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%7B%20%5Ccos%5E%7B4%7D%5Calpha%7D%20%5C%3A%20%2B%20%20%20%5Csin%5E%7B2%7D%20%5Calpha%20%5C%

timurjin [86]

Answer:

Proved

Step-by-step explanation:

$cos^4\alpha +sin^4\alpha =\frac{1}{4}(3+cos4\alpha )\\\\$

Take the Left Hand Side:

$cos^4\alpha +sin^4\alpha\\\\(cos^2\alpha )^2+(sin^2\alpha )^2\\\\(\frac{1+cos2\alpha }{2})^2+(\frac{1-cos2\alpha }{2})^2 \\\\\frac{1+2cos2\alpha +cos^22\alpha }{4}+\frac{1-2cos2\alpha +cos^22\alpha }{4} \\\\$

$\frac{1+2cos2\alpha +cos^22\alpha +1-2cos2\alpha +cos^22\alpha }{4} \\\\\frac{2+2cos^22\alpha }{4} \\\\\frac{1+cos^22\alpha }{2} \\\\\frac{1}{2}(1+cos^22\alpha )\\\\$

$\frac{1}{2}(1+\frac{1+cos4\alpha }{2})$

$\frac{1}{2}(\frac{2+1+cos4\alpha }{2})\\\\\frac{1}{4}(3+cos4\alpha )\\\\$

Hence Proved!

The following identities were used are attached in an image

3 0

3 years ago