Answer:
20 and 60
Step-by-step explanation:
If x=25, angle one is 20 degrees, and angel two is 60 degrees.
To find m<3, we can use the angle sum of triangles, in which the addition all angles in a triangle must be equal to 180°.
In this case:
m<3 +52°+29° = 180°
m<3 + 81° = 180°
m<3 = 180°-81°
m<3 = 99°
To find m<4, we can use adjacent angles on a straight line, where the addition of angles on a straight line must be 180°.
In this case:
m<4 + 99° = 180°
m<4 = 180°-99°
m<4 = 81°
Therefore m<3 is 99° while m<4 is 81°.
Hope it helps!
If y∞x then y=kx where k is constant to find k
k=y/x then substitute the values
k=30/-10=-3 to find x when y is 4
x=y/k=4/-3=-4/3 option A
Answer:
(10x - 5) square units.
Step-by-step explanation:
Let the lengths of equal sides be x units.
Hence, AB + AD + DC = x + x + x = 3x
Therefore, BC = 3x - 2
![Area \: of \: trapezoid \\ = \frac{1}{2} (AD + BC) \times 5 \\ = \frac{1}{2} (x + 3x - 2) \times 5 \\ = \frac{1}{2} (4x - 2) \times 5 \\ = \frac{1}{2} \times 2 (2x - 1) \times 5 \\ = (2x - 1) \times 5 \\ = (10x - 5) \: {units}^{2}](https://tex.z-dn.net/?f=Area%20%20%5C%3A%20of%20%5C%3A%20%20trapezoid%20%20%5C%5C%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%28AD%20%2B%20BC%29%20%20%5Ctimes%205%20%5C%5C%20%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%28x%20%2B%203x%20-%202%29%20%20%5Ctimes%205%20%20%5C%5C%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%284x%20-%202%29%20%20%5Ctimes%205%20%20%5C%5C%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%202%20%282x%20-%201%29%20%20%5Ctimes%205%20%20%5C%5C%20%20%3D%20%282x%20-%201%29%20%5Ctimes%205%20%5C%5C%20%20%3D%20%2810x%20-%205%29%20%5C%3A%20%20%7Bunits%7D%5E%7B2%7D%20)
Answer:
Option A is correct.
Step-by-step explanation:
Given an isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14. we have to find the area of isosceles trapezoid.
An isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14.
From the figure attached , we can see an isosceles trapezoid ABCD,
AB = 8cm and CD=14cm
So we have to find the value of AE which is the height of Trapezoid in order to find area.
In ΔAED
![tan\angle 45 =\frac{AE}{ED}](https://tex.z-dn.net/?f=tan%5Cangle%2045%20%3D%5Cfrac%7BAE%7D%7BED%7D)
⇒ ![AE=1\times 3](https://tex.z-dn.net/?f=AE%3D1%5Ctimes%203)
∴ AE = DE =3cm
![\text{The area of the trapezoid=}\frac{h}{2}\times (a+b)](https://tex.z-dn.net/?f=%5Ctext%7BThe%20area%20of%20the%20trapezoid%3D%7D%5Cfrac%7Bh%7D%7B2%7D%5Ctimes%20%28a%2Bb%29)
h=3cm, a=14cm, b=8cm
![Area=\frac{3}{2}\times(14+8)=\frac{3}{2}\times 22=33 units^2](https://tex.z-dn.net/?f=Area%3D%5Cfrac%7B3%7D%7B2%7D%5Ctimes%2814%2B8%29%3D%5Cfrac%7B3%7D%7B2%7D%5Ctimes%2022%3D33%20units%5E2)
hence, ![\text{The area of the trapezoid is }33 units^2](https://tex.z-dn.net/?f=%5Ctext%7BThe%20area%20of%20the%20trapezoid%20is%20%7D33%20units%5E2)
Option A is correct.