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2 years ago

6

Solve each of the systems below by substitution y = -3/2x (fraction) 3x + 2y = -4

1 answer:

Maslowich2 years ago

8 0

Answer:

GET PHOTOMATH

Step-by-step explanation:

<h2>DOWNLOAD PHOTOMATH</h2><h2 /><h2 /><h2 /><h2>hope this helps bro :)</h2>

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What is the solution to -3x+23-7?<br> O x>-12<br> O x>12<br> O x<12<br> O x<-12

netineya [11]

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2 years ago

Find the length of x. Assume the triangles are similar.

Veronika [31]

Answer:

x = 32

Step-by-step explanation:

The longest side is double the length of the shortest side, so x is 2·16 = 32.

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3 years ago

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2 years ago

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Verify identity: <br><br> (sec(x)-csc(x))/(sec(x)+csc(x))=(tan(x)-1)/(tan(x)+1)

Nikitich [7]

So hmmm let's do the left-hand-side first

$\bf \cfrac{sec(x)-csc(x)}{sec(x)+csc(x)}\implies \cfrac{\frac{1}{cos(x)}-\frac{1}{sin(x)}}{\frac{1}{cos(x)}+\frac{1}{sin(x)}}\implies 
\cfrac{\frac{sin(x)-cos(x)}{cos(x)sin(x)}}{\frac{sin(x)+cos(x)}{cos(x)sin(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)sin(x)}\cdot \cfrac{cos(x)sin(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

now, let's do the right-hand-side then

$\bf \cfrac{tan(x)-1}{tan(x)+1}\implies \cfrac{\frac{sin(x)}{cos(x)}-1}{\frac{sin(x)}{cos(x)}+1}\implies \cfrac{\frac{sin(x)-cos(x)}{cos(x)}}{\frac{sin(x)+cos(x)}{cos(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)}\cdot \cfrac{cos(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

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2 years ago