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3 years ago

25PTS!!!! PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!

Mathematics

2 answers:

AleksAgata [21]3 years ago

7 0

Answer:

The answer is B.

Step-by-step explanation:

You have to have a straight line and it has to go through the origin or else its not proportional

tiny-mole [99]3 years ago

3 0

Answer:

A.) A straight line can be drawn through all the points and the line passes through the point (0, 0)

Step-by-step explanation:

When a line is straight, drawn through all points, and passes through the origin, that is how you know it's proportional.

B. would be incorrect because a line would have to be drawn through tall points to show that it is proportional

C. the first part of c would be correct but a line doesn't have to pass through (0,3) it has to pass through (0,0) also known as the origin

D. This answer is also incorrect. A line always has to pass through (0,0) to be proportional

Hope this helps :D

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{(−1, 5), (2, 8), (5, 3), (13, −4)} what are the range

makkiz [27]

$(x;\ y)\\\\(-1, \fbox5), (2, \fbox8), (5, \fbox3), (13, \fbox{-4})\\\\\boxed{The\ range:y\in\{-4;\ 3;\ 5;\ 8\}}$

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3 years ago

The region bounded by y = e−x2, y = 0, x = 0, and x = b (b > 0) is revolved about the y-axis. (Round your answers to three de

kari74 [83]

Answer:

0.982 * $\pi$ = 3.085 cubic units

Step-by-step explanation:

To find the volume of the solid generated by a region that is bounded by lines where x = 0 , x (b) = 2 we apply the formula given in the attachment below

the required region boundaries are

y = e^-x2 , y = 0 , x = 0, x = b ( b >0)

attached below is a detailed solution of the problem

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3 years ago

Which classification describes AMNO with vertices M(2, -3), N(3, 1), and 0(-3, 1)?

Sonja [21]

Answer:

Option D

Step-by-step explanation:

32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).

Distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the expression,

Distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between M(2, -3) and N(3, 1) will be,

MN = $\sqrt{(3-2)^2+(1+3)^2}$

= $\sqrt{1+16}$

= $\sqrt{17}$

Distance between M(2, -3) and O(-3, 1),

MO = $\sqrt{(2+3)^2+(-3-1)^2}$

= $\sqrt{25+16}$

= $\sqrt{41}$

Distance between N(3, 1) and O(-3, 1),

NO = $\sqrt{(3+3)^2+(1-1)^2}$

= 6

Condition for right triangle,

c² = a² + b² [Here c is the longest side of the triangle]

By this property,

MO² = MN² + NO²

$(\sqrt{41})^2=(\sqrt{17})^2+6^2$

41 = 17 + 36

41 = 51

False.

Therefore, given triangle is not a right triangle.

Since, length of all sides are not equal, given triangle will be a scalene triangle.

Option D is the correct option.

5 0

3 years ago

Consider an experiment with a deck of 52 playing cards, in which there are 13 cards in each suit, two suits are black, and two s

lakkis [162]

Answer:

P (E1) = 1/2 or 50%

P (E2) = 3/13 or 23%

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of playing cards = 52

Number of suits = 4

Number of cards per suit = 13

Number of black suits = 2

Number of red suits = 2

2. Suppose E1 = the outcome is a red card and E2 = the outcome is a face card (K, Q, J). Determine P(E1 or E2).

P (E1) = Number of red cards/Total of playing cards

P (E1) = 26/52 = 1/2 = 50%

P (E2) = Number of face cards/Total of playing cards

P (E2) = 12/52 = 3/13 = 23%

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Ymorist [56]

There was 22 more shakers of salt than pepper

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3 years ago

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