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goblinko [34]
3 years ago
15

Which table shows a proportional relationship between x and y ?

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

Table C

Step-by-step explanation:

Given

Table A to D

Required

Which shows a proportional relationship

To do this, we make use of:

k = \frac{y}{x}

Where k is the constant of proportionality.

In table (A)

x = 2, y = 4

k = \frac{y}{x}

k = \frac{4}{2}

k = 2

x = 4, y = 9

k = \frac{y}{x}

k = \frac{9}{4}

k = 2.25

Both values of k are different. Hence, no proportional relationship

In table (B)

x = 3, y = 4

k = \frac{y}{x}

k = \frac{4}{3}

k = 1.33

x = 9, y = 16

k = \frac{y}{x}

k = \frac{16}{9}

k = 1.78

Both values of k are different. Hence, no proportional relationship

In table (C):

x = 4, y = 12

k = \frac{y}{x}

k = \frac{12}{4}

k = 3

x = 5, y = 15

k = \frac{y}{x}

k = \frac{15}{5}

k = 3

x = 6, y = 18

k = \frac{y}{x}

k = \frac{18}{6}

k = 3

This shows a proportional relationship because all values of k are the same for this table

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This is one pathway to prove the identity.

Part 1

\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity \sin^2(\theta)+\cos^2(\theta) = 1 in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

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What does x equal in 7+2/5x=-5
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Answer:

x = -30

Step-by-step explanation:

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simplify ( 2/5x = 12 )

multiply both sides by 5 ( 2/5x times 5 = 5 (-12) )

simplify ( 2x = -60 )

divide both sides by 2 ( 2x / 2, -60 / 2 )

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