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goblinko [34]
3 years ago
15

Which table shows a proportional relationship between x and y ?

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

Table C

Step-by-step explanation:

Given

Table A to D

Required

Which shows a proportional relationship

To do this, we make use of:

k = \frac{y}{x}

Where k is the constant of proportionality.

In table (A)

x = 2, y = 4

k = \frac{y}{x}

k = \frac{4}{2}

k = 2

x = 4, y = 9

k = \frac{y}{x}

k = \frac{9}{4}

k = 2.25

Both values of k are different. Hence, no proportional relationship

In table (B)

x = 3, y = 4

k = \frac{y}{x}

k = \frac{4}{3}

k = 1.33

x = 9, y = 16

k = \frac{y}{x}

k = \frac{16}{9}

k = 1.78

Both values of k are different. Hence, no proportional relationship

In table (C):

x = 4, y = 12

k = \frac{y}{x}

k = \frac{12}{4}

k = 3

x = 5, y = 15

k = \frac{y}{x}

k = \frac{15}{5}

k = 3

x = 6, y = 18

k = \frac{y}{x}

k = \frac{18}{6}

k = 3

This shows a proportional relationship because all values of k are the same for this table

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Find the value of k if (x-3) is a factor of P(x)=2x3-5x2+3x+k
blsea [12.9K]

Answer:

k = -18

Step-by-step explanation:

If x-3 is a factor, what this means is that if we substitute;

x = 3 into the equation, we should get 0

This is from the factor theorem

Thus ;

P(3) = 0 = 2(3)^3 -5(3)^2 + 3(3) + k

0 = 54 - 45 + 9 + k

k + 18 = 0

k = -18

4 0
3 years ago
An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov
babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this.  This will give us the two times that the object is at exactly 500 meters.  The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using our values for a, b and c,

x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds.  This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

6 0
3 years ago
Which is the more precise measurement? *
RSB [31]

Answer:

19.775

Step-by-step explanation:

I assume your asking which number goes the most in depth to find that look for the number that has the most decimal places

6 0
2 years ago
Please help! I will give brainliest to the first correct answer!
Leviafan [203]

Answer:

A)

Step-by-step explanation:

check that the formula in A works . . .

the 7th term should be 320

a(320) = 5(2)^7-1

= 5(2)^6

= 5(64)

= 320

6 0
3 years ago
on Tuesday pierce ran 3/4 mile and walked 3/4 on Wednesday he ran 2/4 mile and walk 1 1/4 miles hiw much farther did pierce run
Korvikt [17]

Answer:

On Tuesday

3/4 + 3/4 = 3/2 = 1 1/2 = 1.5

On Wednesday

2/4 + 1 1/4 = 7/4 = 1 3/4 = 1.75

Then we subtract

1.75 - 1.5 = 0.25


6 0
3 years ago
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