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Colt1911 [192]
4 years ago
5

According to ohms law if you don't change the value of the resistor and you double the voltage in a circuit the amount of curren

t flowing will _______.
A. Be multiplied by the amount of resistance
B. Remain the same also
C. Divide it in half
D. Double
Physics
1 answer:
padilas [110]4 years ago
5 0

Answer: D (doubled)

According to ohm's law

                      I = V/R ,

                      V = IR ;   R = constant and V is doubled

  From the equation

                      V is directly proportional to the current, and it is given that R is constant ;

                    2V = 2I. R    since R = constant

                      Hence I is doubled.

                     

                   

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A young man exerted a force of 9000N on a stalled car but was unable to move it. How much work was done?
rodikova [14]

Answer:

No work was done at all.

Explanation:

Work is only done when a force is exerted and it moves an object. However, when the man exerted his force on the car, the car did not move at all. Therefore, no work was done.

7 0
4 years ago
Unbalanced forces cause a change in motion.<br><br> How do you know this?
ololo11 [35]

Answer:

This happens in two ways. If an object is at rest and an unbalanced force pushes or pulls the object, it will move. Unbalanced forces can also change the speed or direction of an object that is already in motion.

Explanation:

5 0
3 years ago
Where do most stars fall on the Hertzsprung-Russell diagram?
Alex_Xolod [135]

Answer:

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7 0
2 years ago
What potential difference is required to cause 4.00 a to flow through a resistance of 330 ω?
Alisiya [41]
We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
\Delta V = I R
where
\Delta V is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance

In our problem, I=4.00 A and R=330 \omega, so the potential difference is
\Delta V = IR=(4.00 A)(330 \omega)=1320 V
7 0
3 years ago
An object is dropped from rest from a 70.6 m tower. Air resistance is negligible. After 0.32 seconds, what is magnitude and dire
dem82 [27]

Answer:

<em>1,378.9ms²</em>

Explanation:

Given the following

Distance S = 70.6m

Time t = 0.32secs

Initial velocity = 0m/s

Required

Acceleration

Using the equation of motion

S = ut+1/2at²

Substitute

70.6 = 0+1/2a(0.32)²

70.6 = 0.0512a

a = 70.6/0.0512

a = 1,378.9

<em>Hence the acceleration is 1,378.9ms²</em>

7 0
3 years ago
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