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Marat540 [252]
3 years ago
12

Which of these is always conserved in a collision in a closed system?

Physics
2 answers:
lara [203]3 years ago
7 0
<h3><u>Answer;</u></h3>

A) momentum and energy

<h3><u>Explanation;</u></h3>
  • There are two types of collisions that relate to momentum: elastic and inelastic.
  • In a closed system, which means that there are no external forces acting on the objects that collide, both types of collisions follow the Law of Conservation of Momentum, which states that the total amount of momentum before a collision is equal to the total amount of momentum after a collision.
  • In an elastic collision, not only is momentum is conserved, but also kinetic energy, while in  an inelastic collision, momentum is conserved, but the total kinetic energy of the system is not conserved.
Bumek [7]3 years ago
4 0

Answer:

B) momentum and mechanical energy

Explanation:

In classical physics, a closed system is a system that does not exchange any matter with the surrounding, and on which there are no external forces acting on it.

Due to this definition, we have the following consequences:

- In a collision in a closed system, momentum is always conserved. This is because there is exchange of matter with the surroundings (so, no mass can be lost), and also because there are no external forces acting on the objects inside the system. In fact, the variation of the total momentum of the system is related to the net force acting on the system:

F=\frac{\Delta p}{\Delta t}

but since the net force F is zero, then the variation of momentum, \frac{\Delta p}{\Delta t}, is also zero, therefore the momentum is constant.

- Also, mechanical energy is conserved. Mechanical energy is the sum of potential energy and kinetic energy of the system: again, since there are no external forces acting on the system, energy cannot be dissipated, so the total energy of the system cannot change.

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Which of the following statements is true? *
lozanna [386]

Answer: B Genes make up chromosomes

Explanation: hope it helps

7 0
3 years ago
A hollow ball with a diameter of 3.81 cm has an average density of 0.0842 g/cm3. What force must be applied to hold it stationar
vfiekz [6]

Answer:

0.26

Explanation:

Given that :

Diameter of ball = 3.81 cm = 3.81/100 = 0.0381 m

Radius (r) = 0.0381 / 2 = 0.01905 m

Average density of ball (Db) = 0.0842 g/cm³ = (0.0842 / 1000)kg / 10^-6 = 0.0842/ 1000 * 10^6 = 84.2kg/m³

Density of water (Dw) = 1000kg/m³

Volume of hollow ball: (4/3) * pi * r³

V = (4/3) * π * 0.01905^3

V = 0.0000289583 m³

Required force = (Dw * V * g) - (Db * V * g)

= (1000 * 0.0000289583 * 9.8) - (84.2 * 0.0000289583 * 9.8)

= 0.259896109172

= 0.2598 N

6 0
3 years ago
Select the correct answer. Rita is a registered dietician. What does her work entail? A. prescribing medication for clients B. c
yarga [219]

Answer:

D

Explanation:

The answer is D because:

A) Only doctors are allowed to prescribe medications.

B) Rita is not a chef/cook.

C) Rita is not a personal trainer

D) The job of a dietican is to provide reccomendations to their clients in order for them to implement a healthy lifestyle via consuming what is best for them.

Hope this helps :)

4 0
3 years ago
A 55 kgkg meteorite buries itself 5.5 mm into soft mud. The force between the meteorite and the mud is given by F(x)F(x) = (630
sashaice [31]

Answer:

W = 1.44 10⁻⁷ J

Explanation:

The expression for the job is

          W = ∫ F. dx

Where the point is the scalar product in this case the direction of the meteor and the depth is parallel, whereby the scalar product is reduced to the ordinary product

          W = 630 ∫ x³ dx

          W = 630 x⁴ / 4

Let's evaluate between the lower limit x = 0, w = 0 to the upper limite the point at x = 5.5 10⁻³ m

            W = 157.5 ((5.5 10⁻³)⁴ -0)

            W = 1.44 10⁻⁷ J

6 0
3 years ago
This is the sum of all the forces applied to an object. It is usually separated into a horizontal and vertical component.
evablogger [386]

Answer: Net Force, also is referred to as Resultant Force

5 0
3 years ago
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