#1. look at the individual probability first.
A dice has 6 sides. The numbers > 2 are {3, 4, 5, 6}. So the chance of rolling a number > 2 is 4/6 or 2/3 simplified.
Multiples of 3 on a dice are {3, 6}. So the chance of rolling a multiple of 3 is 2/6 or 1/3 simplified.
Rolling a dice is an independent event, like flipping a coin the previous roll does not have an effect on the outcome of the next roll. So when you see the word AND connecting the outcomes, you multiply them.
Prob of rolling >2 AND then multiple of 3 = (2/3)*(1/3)
= 2/9
#2. The total socks in the drawer: 8+8+4= 20 socks
The probability of first drawing a blue sock is 8/20 or 2/5 simplified.
Since the question does not say the socks are put back in the drawer, the total number of socks and number of blue socks decrease by 1 after the first draw. This makes the next draw dependent on the first.
The probability of drawing a blue sock is then: 7/19
because there's a blue sock missing.
Probability of drawing blue sock AND then a blue sock (without replacement)
= (2/5)*(7/19)
= 14/95
The answer is no because the problem has no solution. Hope this helps
X=-3/2. The value of f(-1). All you do is plug the numbers In.
Answer:
answer is 10
Step-by-step explanation:
(4x+12)+(4x+12)+(5x+26)=180[sum of isosceles triangles]
8x+34+5x+26=180
X=10
