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3 years ago

4 oranges at Juicy Deals grocery store cost $6. For the price of $15 you can buy 10 oranges. True or false: The relationship

2 answers:

7 0

Hi! The answer is true because if you divide 6/4 you get 1.5 so 1.5 X 4 is 6 so you know that is proportional and 15/10 is 1.5 so you know that is proportional as well.

1.5 X 4 = 6
1.5 X 10 = 15

Since they both equal 1.5 after you divide them you know it’s proportional. I hope this helped, Goodluck :)

musickatia [10]3 years ago

3 0

Answer:

the answer is true.

4/6

10/15

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Evaluate the double integral.

Fynjy0 [20]

Answer:

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

Step-by-step explanation:

The equation of the line through the point $(x_o,y_o)$ & $(x_1,y_1)$ can be represented by:

$y-y_o = m(x - x_o)$

Making m the subject;

$m = \dfrac{y_1 - y_0}{x_1-x_0}$

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

$m= \dfrac{2-1}{1-0}$

m = 1

Thus;

y - 1 = (1)x

y - 1 = x ---- (1)

The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

$m = \dfrac{1-2}{4-1}$

$m = \dfrac{-1}{3}$

∴

$y-2 = -\dfrac{1}{3}(x-1)$

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

$\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg) dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ([y^2(-4y+8)] \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( -4y^3+8y^2 \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \bigg [\dfrac{ -4y^4}{4}+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -y^4+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -16+\dfrac{64}{3} + 1- \dfrac{8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{-45+56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{11}{3}\bigg]$

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

4 0

2 years ago

The volume of

STALIN [3.7K]

100 drops =1fluid ounce 1 drop= 1/100 ounce Hence 10 drops =10/100=1/10

3 0

3 years ago

What are the numbers and called in a number line ??

WARRIOR [948]

Answer:

numbers

Step-by-step explanation:

numbers

8 0

2 years ago

Jimmy collects nickels and dimes. Right now, he has a total of 40 coins in his piggy bank. If there are seven times as many dime

Colt1911 [192]

Number of nickels plus number of dimes equals total number of coins
so
n + d = 40

then they tell us that "there are seven times as many dimes as there are nickels"
this translates to
d = 7n

we then plug that into our first equation
and get
n + 7n = 40

then we solve for n
add like terms
8n = 40

then divide both sides by 8
n = 40/8 = 5

therefore Jimmy has 5 nickels

4 0

3 years ago

On a coordinate plane, a square has points A (negative 5, 2), B (1, 2), C (negative 4, 1), and D (negative 5, negative 4).

Mars2501 [29]

Answer:

-6

Step-by-step explanation: dont know, did math. this is the answer on edge

6 0

3 years ago

Read 2 more answers