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Mars2501 [29]
3 years ago
15

I need help plz hurry before the time is over plz plz ​

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
6 0

Answer:

JK

Step-by-step explanation:

As it is shown in the diagram JK is the segment bisector of MN. That means JK cuts MN in half.

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What’s the value for 2.3 + 4.09 =n
Rashid [163]
Answer:

n = 6.39

Explanation:

2.3 + 4.09 = n
6.39 = n

Swap the sides of the equation
n = 6.39
6 0
3 years ago
During a drive to Arizona, for the first two hours Emily drove at 50 mph,
galina1969 [7]

Answer:

the EXACT answer is 29.16666667

Step-by-step explanation:

First you add 50, 60, and 65 and get 175

she is driving for 6 hours so you divide 175 by six to get the average

Then you get 29.16666667

6 0
3 years ago
If x=-7 is a root of the equation x^2+kx+49=0, then k=​
aleksley [76]

Answer:

k=14

Step-by-step explanation:

Given:

x^{2}+kx+49 = 0

x = -7

Substitution can be used to find the value of k:

(-7)^{2}+(-7)k+49 = 0

49-7k+49 = 0

98 -7k = 0

k = 14

Hope this helps :)

8 0
3 years ago
Please can anyone help???
marta [7]

Answer:

x = -3, y = 0

Step-by-step explanation:

15 - 9 = 6

6 - 9 = -3

0 + 5 = 5

5 +5 = 10

8 0
3 years ago
Bryan’s monthly electric bill is determined by adding a flat administration fee to the product of the number of kilowatt hours o
Sophie [7]
We will form the equations for this problem:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
z = ? Monthly administration fee is notated with z, and that is the this problem's question.
Number of kilowatt hours of electricity used are numbers 1100 and 1500 respectively.
Cost per kilowatt hour is notated with y, but its value is not asked in this math problem, but we can calculate it anyway.
The problem becomes two equations with two unknowns, it is a system, and can be solved with method of replacement:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
----------------------------
(1) z = 113 - 1100*y [insert value of z (right side) into (2) equation instead of z]:
(2) 1500*y + (113 - 1100*y) = 153
-------------------------------------------------
(1) z = 113 - 1100*y
(2) 1500*y + 113 - 1100*y = 153
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y + 113 = 153
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y = 153 - 113
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y = 40
------------------------------------------------
(1) z = 113 - 1100*y
(2) y = 40/400
------------------------------------------------
(1) z = 113 - 1100*y
(2) y = 1/10
------------------------------------------------
if we insert the obtained value of y into (1) equation, we get the value of z:
(1) z = 113 - 1100*(1/10)
(1) z = 113 - 110
(1) z = 3 dollars is the monthly fee.
6 0
3 years ago
Read 2 more answers
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