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Stels [109]
3 years ago
8

Which of the following is not true of client-server applications?

Computers and Technology
1 answer:
Sliva [168]3 years ago
3 0

Answer:

B.

Explanation:

Client-server application is a relationship between a client and a server.

In this relationship, the client (a program) requests a service from the server (the other resource).

The statement that is not true about the client-server applications is they include smart phones, tablets, iPads, laptops, desktop computers.

Rest of the statements concerning client-server relationship are true.

Therefore, option B is the answer.

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PLZZ HELP
kap26 [50]

Answer:

Explanation:

Keep in mind a lossy algorithm will lose information while a lossless algorithm maintains all your original information.

Therefore:

A. False, a lossy algorithm will not allow perfect reconstruction.

B. True, if you don't care about keeping all your information it's easier to compress.

C. False, you can use a lossless algorithm for anything.

D. False, the point of lossless is that you keep all information.

4 0
3 years ago
The destructor automatically executes when the class object goes out of ____.
Tema [17]

Answer:

scope    

Explanation:

Destructor is a member function and it call automatically when the class object goes out of scope.

Out of scope means, the program exit, function end etc.

Destructor name must be same as class name and it has no return type.

syntax:

~class_name() { };

For example:

class xyz{

  xyz(){

        print(constructor);

   }

~xyz(){

        print(destructor);

   }

}

int main(){

    xyz num;

   

}//end program

when the object is create the constructor will called and when the program end destructor will call automatically.

4 0
3 years ago
What function(s) does an interpreter perform with the instructions in a high-level programming language?
allochka39001 [22]

Answer:

Translates and Executes.

Explanation:

5 0
3 years ago
Which code snippet could be used to print the following series?
GaryK [48]
C is the answer, I think
7 0
2 years ago
Write a function that returns a chessboard pattern ("B" for black squares, "W" for white squares). The function takes a number N
Kryger [21]

Answer:

Here is the C++ program.

#include <iostream>  //to use input output functions

using namespace std;  // to access objects like cin cout

 

void chessboard(int N){  // function that takes a number N as parameter generates corresponding board

   int i, j;  

   string black = "B";  // B for black squares

   string white = "W"; // W for white squares

   for(i=1;i<=N;i++){  //iterates through each column of the board

       for(j=1;j<=N;j++){  //iterates through each row of the board

           if((i+j)%2==0)  // if sum of i and j is completely divisible by 2

               cout<<black<<" ";  //displays B when above if condition is true

           else  //if (i+j)%2 is not equal to 0

           cout<<white<<" ";  }  // displays W when above if condition is false

      cout<<endl;    }    }  //prints the new line

       

int main(){    //start of the main function

   int num;  //declares an integer num

   cout << "Enter an integer representing the size of the chessboard: ";  //prompts user to enter size of chess board

   cin >> num;  //reads value of num from user

   chessboard(num); } //calls chessboard function to display N lines consist of N space-separated characters representing the chessboard pattern

Explanation:

The function works as follows:

Lets say that N = 2

two string variables black and white are declared. The value of black is set to "B" and value of white is set to "W" to return a chessboard pattern in B and W squares.

The outer loop for(i=1;i<=N;i++) iterates through each column of the chess board. The inner loop  for(j=1;j<=N;j++) iterates through each row of chess board.

At first iteration of outer loop:

N = 2

outer loop:

i=1

i<=N is true because i=1 and 1<=2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+1) % 2 == 0

(1+1 )% 2 takes the mod of 1+1 with 2 which gives the remainder of the division.

2%2 As 2 is completely divisible by 2 so 2%2 == 0

Hence the if condition evaluates to true. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+2) % 2 == 0

(1+2 )% 2 takes the mod of 1+2 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

The value of j is incremented to 1.

j = 3

Now  

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop to iterate through the next row.

At second iteration of outer loop:

N = 2

outer loop:

i=2

i<=N is true because i=2 and 2 = 2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+1) % 2 == 0

(2+1 )% 2 takes the mod of 2+1 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

W

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+2) % 2 == 0

(2+2 )% 2 takes the mod of 2+2 with 2 which gives the remainder of the division.

4%2 As 4 is completely divisible by 2 so 4%2 == 0

Hence the if condition evaluates to false. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B W

W B

The value of j is incremented to 1.

j = 3

Now  

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop. The value of outer loop variable i is incremented to 1 so i = 3

N = 2

outer loop:

i=3

i<=N is false because i=3 and 3>2

So this outer loop ends.

Now the output of this program is:

B W

W B

Screenshot of this program along with its output is attached.

8 0
3 years ago
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