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3 years ago

I really need help. Can you help me? please? Can you at least take a look at it? thanks.

Mathematics

2 answers:

wlad13 [49]3 years ago

8 0

Answer:

Step-by-step explanation:

The perimeter is all sides added. So using what we know, you get: width+width+26+26=116

Simplify this as 2*width = 116-26-26 and calculate.

Then we find that width = 64/2 = 32

dalvyx [7]3 years ago

7 0

Answer:

A.2width=26+26+116

64/2=32

B.The perimeter is all sides added. So using what we know, you get: width+width+26+26=116 Simplify this as 2*width = 116-26-26 and calculate.Then we find that width = 64/2 = 32

Step-by-step explanation:

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(2/3) i am in need of assistance

adoni [48]

Answer:

what is the assistance

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Suppose an unknown radioactive substance produces 8000 counts per minute on a Geiger counter at a certain time, and only 500 cou

mariarad [96]

Answer:

The half-life of the radioactive substance is of 3.25 days.

Step-by-step explanation:

The amount of radioactive substance is proportional to the number of counts per minute:

This means that the amount is given by the following differential equation:

$\frac{dQ}{dt} = -kQ$

In which k is the decay rate.

The solution is:

$Q(t) = Q(0)e^{-kt}$

In which Q(0) is the initial amount:

8000 counts per minute on a Geiger counter at a certain time

This means that $Q(0) = 8000$

500 counts per minute 13 days later.

This means that $Q(13) = 500$ . We use this to find k.

$Q(t) = Q(0)e^{-kt}$

$500 = 8000e^{-13k}$

$e^{-13k} = \frac{500}{8000}$

$\ln{e^{-13k}} = \ln{\frac{500}{8000}}$

$-13k = \ln{\frac{500}{8000}}$

$k = -\frac{\ln{\frac{500}{8000}}}{13}$

$k = 0.2133$

$Q(t) = Q(0)e^{-0.2133t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.2133t}$

$0.5Q(0) = Q(0)e^{-0.2133t}$

$e^{-0.2133t} = 0.5$

$\ln{e^{-0.2133t}} = \ln{0.5}$

$-0.2133t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.2133}$

$t = 3.25$

The half-life of the radioactive substance is of 3.25 days.

7 0

3 years ago

How many times larger is 4×10 to 6th power than 1 × 10 to the 4th power in scientific notation

goldenfox [79]

4x10 6th power = 280
1x10 4th power =13
So if I'm right 4x10 6power is greater

3 0

3 years ago

Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and

user100 [1]

Answer:

x1Rules=true;

for (i=0; i<2; i++)

for (j=0; j<3; j++)

if (x1[i][j] <= x2[i][j])

{

x1Rules=false;

break;

}

Step-by-step explanation:

The code is written above .

4 0

3 years ago

Calculer x si (x+1/2)^2= 4/9

-Dominant- [34]

Answer:

$x=-\frac{7}{6}\\x=\frac{1}{6}$

Step-by-step explanation:

The equation to solve is:

$(x+\frac{1}{2})^2=\frac{4}{9}$

To get rid of the "square", we need to take square root of both sides:

$\sqrt{(x+\frac{1}{2})^2}=\sqrt{\frac{4}{9}}\\x+\frac{1}{2}=\frac{\sqrt{4}}{\sqrt{9}}$

Then we use algebra to find the value(s) of x. Remember, when we take square root, we have to add up a "+-" (on the right side). Shown below:

$x+\frac{1}{2}=+-\frac{\sqrt{4}}{\sqrt{9}}\\x+\frac{1}{2}=+-\frac{2}{3}\\x=\frac{2}{3}-\frac{1}{2}=\frac{1}{6}\\x=-\frac{2}{3}-\frac{1}{2}=-\frac{7}{6}$

So these are 2 answers for x.

5 0

3 years ago