Basing on the question the volume of metal should be equal to the volume of the wire.
We already have the volume of the metal which is 1cm cube.
To get the volume of the wire, the equation is V=3.14 x r^2 x h
since the volume of the wire is same as the volume of the metal, we simply substitute.
1 cm^3 = 3.14 x r^2 x h
h is the length of the wire.
the diameter of the wire is 1 mm or 0.1 cm, to get the radius we divide it by 2, 0.1 cm / 2 is 0.05 cm, we substitute
1 cm^3= 3.14 x (0.05 cm)^2 x h
1 cm^3= 3.14 x 0.0025 cm^2 x h
h = 0.00785 cm^2 / 1 cm^3
h=0.00785 cm or 0.0785 mm.
Answer:
B. y = 3x
Step-by-step explanation:
Since the y-axis is going up by 6's and the x-axis is going up by 2's, we can see that we would need to multiply the x-axis values by 3 to get our y-values. Therefore, our linear equation for this graph is y = 3x.
Let a = weight of large box in pounds
Let b = weight of small box in pounds
(1) 65a + 70b=4000
(2) a+b=60
Now we can simultaneously solve these equations.
a = 60 - b. Hence 65(60 - b) + 70b = 4000 So 3900 + 5b = 4000 and 100 = 5b hence b = 20.
SImilarly a = 40. Now we can verify too by putting in the calculated values.
Answer:
there is 21 boys
Step-by-step explanation:
hope that helps
The events are independent. By definition, it means that knowledge about one event does not help you predict the second, and this is the case: even if you knew that you rolled an even number on the first cube, would you be more or less confident about rolling a six on the second? No.
An example in which two events about rolling cubes are dependent could be something like:
Event A: You roll the first cube
Event B: The second cube returns a higher number than the first one.
In this case, knowledge on event A does change you view on event B (and vice versa): if you know that you rolled a 6 on the first cube you don't want to bet on event B, while if you know that you rolled a 1 on the first cube, you're certain that event B will happen.
Conversely, if you know that event B has happened, you are more likely to think that the first cube rolled a small number, and vice versa.
