Answer:
what is the assistance
Step-by-step explanation:
Answer:
The half-life of the radioactive substance is of 3.25 days.
Step-by-step explanation:
The amount of radioactive substance is proportional to the number of counts per minute:
This means that the amount is given by the following differential equation:

In which k is the decay rate.
The solution is:

In which Q(0) is the initial amount:
8000 counts per minute on a Geiger counter at a certain time
This means that 
500 counts per minute 13 days later.
This means that
. We use this to find k.







So

Determine the half-life of the radioactive substance.
This is t for which Q(t) = 0.5Q(0). So







The half-life of the radioactive substance is of 3.25 days.
4x10 6th power = 280
1x10 4th power =13
So if I'm right 4x10 6power is greater
Answer:
x1Rules=true;
for (i=0; i<2; i++)
for (j=0; j<3; j++)
if (x1[i][j] <= x2[i][j])
{
x1Rules=false;
break;
}
Step-by-step explanation:
The code is written above .
Answer:

Step-by-step explanation:
The equation to solve is:

To get rid of the "square", we need to take square root of both sides:

Then we use algebra to find the value(s) of x. Remember, when we take square root, we have to add up a "+-" (on the right side). Shown below:

So these are 2 answers for x.