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charle [14.2K]
3 years ago
11

(07.08 MC) The graph below shows the price, y, in dollars, of different amounts of peanuts, x, in pounds: Which equation best re

presents the relationship between x and y? (5 points) Select one: a. y = x + 6 b. y = 3x c. y = 6x d. y = x + 3

Mathematics
1 answer:
morpeh [17]3 years ago
8 0

Answer:

B. y = 3x

Step-by-step explanation:

Since the y-axis is going up by 6's and the x-axis is going up by 2's, we can see that we would need to multiply the x-axis values by 3 to get our y-values. Therefore, our linear equation for this graph is y = 3x.

You might be interested in
Determine whether the equation is exponential growth or exponential decay
Harman [31]

9514 1404 393

Answer:

  1. decay
  2. decay
  3. growth

Step-by-step explanation:

If the base of a positive exponential is greater than 1, the function is a growth function. If it is less than 1, the function decays.

Remember that a^-1 = 1/a, so a negative exponential can be transformed to a positive one.

__

1. y = 2(11/5)^-x = 2(5/11)^x . . . . 5/11 < 1, so decay

2. y = e^(-2x) = (1/e^2)^x . . . . 1/e^2 < 1, so decay

3. y = 1/4e^x . . . . e > 1, so growth

_____

e ≈ 2.71828 . . . an irrational number

4 0
3 years ago
A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ? units. The point (-
olganol [36]
Hello,

The circle has like equation: (x+3)²+(y-2)²=r²

If x=1 then y=5 ==>(1+3)²+(5-2)²=r²==>4²+3²=r²==>r=5 (the radius)

if x=-7 then (-7+3)²+(y-2)²=25 ==>  (y-2)²=25-16==>y=2+3 or y=2-3
The points (-7,5) and (-7,-1) are on the circle.
3 0
3 years ago
Read 2 more answers
True or False. A parallelogram sometimes has opposite sides that are not congruent.
Nutka1998 [239]

Answer:

false . false is the answer

4 0
3 years ago
What the answer please
jeka94

Answer:

The right option should be c

Step-by-step explanation:

The measure of (OH-)

4 0
2 years ago
The thickness of a plastic film (in mils) on a substrate material is thought to be influenced by the temperature at which the co
statuscvo [17]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if rising the process temperature reduces the thickness of the plastic film that coats a substrate material To do so, two samples of substrates are coated at different temperatures:

Sample 1

X₁: Thickness of the plastic film after the substrate is coated at 125F

n₁=11

X[bar]₁= 101.28

S₁= 5.08

Sample 2

X₂: Thickness of the plastic film after the substrate is coated at 150F

n₂= 13

X[bar]₂= 101.70

S₂= 20.15

Does the data support this claim? Use the P-value approach and assume that the two population standard deviations are not equal.

Now if the higher the heat, the thinner the thickness of the plastic coating, then the average thickness of the coating done at 150F should be less than the average thickness of the coating done at 125F, symbolically: μ₂ < μ₁

Then the hypotheses are:

H₀: μ₂ ≥ μ₁

H₁: μ₂ < μ₁

α:0.05 (there is no α level stated so I've chosen the most common one)

Assuming that both variables have a normal distribution since the population standard deviations are not equal, the statistic to use is the Welch's t-test:

t= \frac{(X[bar]_2-X[bar]_1)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } } ~~t_w

t_{H_0}= \frac{(101.7-101.28)-0}{\sqrt{\frac{(20.15)^2}{13} +\frac{(5.08)^2}{11} } } = 0.072

This test is one-tailed to the left, meaning that you'll reject the null hypothesis at small values of t. The p-value is also one-tailed and has the same direction as the test. To calculate it you have to first calculate the degrees of freedom of the Welch's t:

Df_w= \frac{(\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S^2_1}{n_1})^2 }{n_1-1}+\frac{(\frac{S^2_2}{n_2} )^2}{n_2-1}  }

Df_w= \frac{(\frac{5.08^2}{11} +\frac{20.15^2}{13} )^2}{\frac{(\frac{5.08^2}{11})^2 }{10} +\frac{(\frac{20.15^2}{13} )^2}{12} } = 13.78

The distribution is a Student's t with 13 degrees of freedom, then you can calculate the p-value as:

P(t₁₃≤0.072)= 0.4718

Using the p-value approach, the decision rule is:

If the p-value ≤ α, the decision is to reject the null hypothesis.

If the p-value > α, the decision is to not reject the null hypothesis.

The p-value is greater than the significance level, so the decision is to nor reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to support the claim that the average thickness pf the plastic coat processed at 150F is less than the average thickness pf the plastic coat processed at 125F.

I hope you have a SUPER day!

4 0
3 years ago
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