Step-by-step explanation:
step 1 .simply N/6 equation at the end of step 1 is (7+n/6)-1=0
step 2. rewrite the whole as an equivalent fraction 7=7/1=7.6/6
<u>Answer:</u>
The value of x is in the solution set of 3(x – 4) ≥ 5x + 2 is -10
<u>Solution:</u>
Need to determine which value of x from given option is solution set of 3(x – 4) ≥ 5x + 2
Lets first solve 3(x – 4) ≥ 5x + 2
3(x – 4) ≥ 5x + 2
=> 3x – 12 ≥ 5x + 2
=> 3x – 5x ≥ 12 + 2
=> -2x ≥ 14
=> -x ≥ 7
=> x ≤ -7
All the values of x which are less than or equal to -7 is solution set of 3(x – 4) ≥ 5x + 2. From given option there is only one value that is -10 which is less than -7
Hence from given option -10 is solution set of 3(x – 4) ≥ 5x + 2.
Sin is opposite over hypotenuse so the answer would be sqrt3\2
Let's focus on the given equation. The C represents the cost, while the x must be the number of tacos, which is what we're solving for. Since we're given the boundary that C must be 300, then the solution would be:
300 = x² - 40x + 610
x² - 40x + 310 = 0
Apply the quadratic formula where a = 1, b = -40 and c = 310. The roots of x are:
x = 29.49≈30
x = 10.51≈11
<em>Thus, she needs to sell either 30 or 11 tacos.</em>