So 1/9-16z^2 this is a diffirence of two perfect squares thing
so (1/3)^2-(4z)^2
so ((1/3)-4z)((1/3)+4z)
The solution is y < -1/5
In order to find the answer to this problem, follow the order of operations for solving equations/inequalities.
444 + 555y < 333 -----> Subtract 444 from both sides
555y < -111 -----> Divide both sides by 555
y < -1/5
Answer:
9.
Step-by-step explanation:
It's given that A = 16. It shows that B = A-7, so that would mean B is 16-7, which is 9.
7 times 6 is 42
91 divided by 7 is 13
