Answer:
False
Step-by-step explanation:
So 3 2/3 is about 3.67 so it would go in between 3.65 and 3.7. So it would be the second answer.
Answer:
From the graph: we have the coordinates of RST i.e,
R = (2,1) , S = (2,-2) , T = (-1,-2)
Also, it is given the scale factor
and center of dilation C (1,-1)
The mapping rule for the center of dilation applied for the triangle as shown below:

or
or

Now,
for R = (2,1)
the image R' =
or

⇒ R' =
For S = (2, -2) ,
the image S'=
or

⇒ S' =
and For T = (-1, -2)
The image T' =
or

⇒ T' = 
Now, label the image of RST on the graph as shown below in the attachment:
Answer:
y=2x^2 + 2x - 3 x -2 -1 0 1 2
Step By Step Explanation:
The values can be find by plugging the x values in the equation which gives us the y value ,
x -2 -1 0 1 2
y 1 -3 -3 1 9
(b) Plot the points on the graph and join by a smooth curve.
(c) The line y=1 will be passing through 1 and parallel to x-axis.
(d) solve 2x^2 + 2x - 3 = 1
Subtract 1 from both the sides ,
2x^2 + 2x - 2 = 0
Factoring out the 2 from the equation ,
2(x^2 + x - 1) = 0
x^2 + x - 1 = 0
Apply the quadratic formula
x=(-1-sqrt(5))/2 and x = (-1+sqrt(5))/5