Given that PQ and RS are drawn with KL as tranversal intersecting PQ at M and RS at point N. Angle QMN is congruent to angle LNS because they are alternate to each other. The theorem that Kari can use to show that the meansure of QML is supplementary to the measure of angle SNK is Alternate Exterior Angles Theorem.
This is because angle KNR is equal to QML by alternate exterior angles theorem so is angle MLP and SNK
Answer:
C or B
Step-by-step explanation:
Answer:
y = 4x - 19
Step-by-step explanation:
The line is parallel to the line whose equation is;
y = 4x + 1
Parallel lines have the same slope so the slope of our line is 4.
The line passes through point (5,1)
Slope = change in y ÷ change in x
Taking another point (x,y) on the line,
Slope =
= 4
y - 1 = 4x - 20
y = 4x - 19
Answer:
-47/100
Step-by-step explanation:
Answer:
the answer to the inequality is
Step-by-step explanation:
x = 3