Solve for y:
3 y - 2 y + 5 = 11
Grouping like terms, 3 y - 2 y + 5 = (3 y - 2 y) + 5:
(3 y - 2 y) + 5 = 11
3 y - 2 y = y:
y + 5 = 11
Subtract 5 from both sides:
y + (5 - 5) = 11 - 5
5 - 5 = 0:
y = 11 - 5
11 - 5 = 6:
Answer: | y = 6 ; thus 1 Answer
The distance between (x1, y1) and (x2, y2) is found using the Pythagorean theorem. It is ...
For your values of (x1, y1) = (6, 5) and d = 5, substituting into the formula gives
This matches the first selection.
This is a conversion problem (meters to nanometers) so all you do is use the values given to you in the question.
We know that 1 meter = 1*10^9 nanometers, meaning that for every one meter is also 1*10^9 nanometers and vice versa. So we can set up the "train tracks"
[
tex] \frac{1*10^9 nanometers}{1 meter} * (1*10^-5 meters) [/tex]
I set it up that way because it cancels out the units "meters" since 1 meter is in the denominator and the other meter is in the numerator.
Then I'll be left with:
Now we can solve as is.