All categories

3 years ago

What scale factor was applied to the first rectangle to get the resulting image?

2 answers:

8 0

So, the arrow is telling us that we're going from the small rectangle to the big rectangle.

The 3 and the 7.5 are on the same side of the rectangle, right? So, let's try this backwards.

To get to 3 from 7.5, what do we divide by? (Hint: (7.5)/(3) Divide.)

The scale factor is the answer of the division, which is 2.5. We multiply 3 by 2.5 to get to 7.5.

Dima020 [189]3 years ago

5 0

Answer:

Wrong its 2.5 kids hope i helped or this is the correct problem your doing.

Step-by-step explanation:

You might be interested in

Write the equation of the parabola in standard form.

Inessa [10]

I don’t know if that’s what you wanted but I hope I helped ;D (sorry for my bad english)

6 0

2 years ago

(8+5i) + (10+6i)-(3+6i)

Natali [406]

Answer:

15 + 5i

Step-by-step explanation:

$(8+5i) + (10+6i)-(3+6i) \\ \\ = 8 + 5i + 10 + 6i - 3 - 6i \\ \\ =( 8 + 10 - 3 )+ (5i + 6i - 6i )\\ \\ = 15 + 5i$

8 0

3 years ago

Please help me. i am so confused please

sveticcg [70]

Answer:

what is the question above what you are showing in the picture ?

Step-by-step explanation:

it will help a lot

5 0

3 years ago

Read 2 more answers

a 16 inch wire is to be cut. one piece is to be bent into the shape of a square, whereas the other piece is to be bent into the

Lyrx [107]

1. Let x be a length of square side, then the square perimeter is 4x (you need to cut 4x from 16 in. to make a square with side x in.). Then 16-4x is remained length of wire and you have to make form this piece a rectangle with sides one of which is twice bigger than another. If y is length of the smaller side, then 2y is length of the bigger side and rectangle perimeter is y+2y+y+2y=6y. You have 16-4x in. of wire left, so 6y=16-4x and $y= \frac{16-4x}{6}$ .

2.
$A_{square}=x^2 \\ A_{rectangle}=y\cdot 2y=\frac{16-4x}{6}\cdot2\cdot\frac{16-4x}{6}= \frac{(16-4x)^2}{18} \\ A(x)=A_{square}+A_{rectangle}=x^2+\frac{(16-4x)^2}{18}$ .

3. Find the derivative of the function A(x):
$A'(x)=2x+ \dfrac{2(16-4x)\cdot(-4)}{18} =2x- \dfrac{4(16-4x )}{9}$ .

4. Solve the equation A'(x)=0:
$2x- \dfrac{4(16-4x )}{9}=0 \\ 18x-64+16x=0 \\ 34x=64 \\ x= \frac{32}{17}$

5. Since $y= \frac{16-4x}{6}$ you have

$y= \dfrac{16-4 \frac{32}{17} }{6} = \dfrac{16\cdot17-4\cdot32}{6\cdot 17} = \dfrac{24}{17}$ .

Answer: <span>the width of the rectangle is $\frac{24}{17}$ </span>

6 0

3 years ago

I really need help with this thank you

eduard

Answer:

The photo is not clear post a clear photo then i will see that

8 0

3 years ago

Read 2 more answers