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Marrrta [24]
2 years ago
8

Slide the green dot Use the number line to plot the numbers. Then arrange

Mathematics
1 answer:
lbvjy [14]2 years ago
6 0

I don't see any green dot, sorry.

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Please help me solve this!!!!!!
BabaBlast [244]

Answer:

C. 9

Step-by-step explanation:

y = -4x^2 + 2kx

subtitute 3:

y = -4(9)^2 + 2k(9)

y = -4(81) + 18k

let y = 0

=> 0 = -324 + 18k

=> k = 324/18 = 9

this is my calculations hope it helps

4 0
2 years ago
Read 2 more answers
there are 25 pigs and chickens on a farm. if there are 90 legs counted altogether, then how many of each animal are there?
e-lub [12.9K]

Answer:

115

Step-by-step explanation:

25+90

7 0
3 years ago
Read 2 more answers
Helppppppppppppppppppp will hive brainliest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Alik [6]

Answer:

the constant propertianr would be 4!

Step-by-step explanation:

1 times 4 is 4

2 times 4 is 8

3 times 4 is 12

4 times 4 is 16

4 0
2 years ago
A sports teacher had 1025 sweets. After distributing these equally amongst all the participants in a sports meet, he had just 1
Cerrena [4.2K]

Step-by-step explanation:

Since it remains only 1 sweet, we can subtract it from the total and get the amount of sweets distributed (=1024).

As all the sweets are distributed equally, we must divide the number of distributed sweets by all its dividers (excluding 1024 and 1, we'll see later why):

1) 512 => 2 partecipants

2) 256 => 4 partecipants

3) 128 => 8 partecipants

4) 64 => 16 partecipants

5) 32 => 32 partecipants

6) 16 => 64 partecipants

7) 8 => 128 partecipants

9) 4 => 256 partecipants

10) 2 => 512 partecipants

The number on the left represents the number of sweets given to the partecipants, and on the right we have the number of the partecipants. Note that all the numbers on the left are dividers of 1024.

Why excluding 1 and 1024? Because the problem tells us that there remains 1 sweet. If there was 1 sweet for every partecipant, the number of partecipants would be 1025, but that's not possible as there remains 1 sweet. If it was 1024, it wouldn't work as well because the sweets are 1025 and if 1 is not distributed it goes again against the problem that says all sweets are equally distributed.

5 0
2 years ago
Solve for x and y
bekas [8.4K]

Answer:

x = 2√2

y = 2√6

Step-by-step explanation:

Consider the ratio of the two legs of the two smaller interior right triangles. (refer to attached diagrams for the triangles - I have outlined one in blue and the other in red)

These will be equal since the triangles are similar

shorter leg : longer leg

(blue triangle = red triangle)

⇒ x : 4 = 2 : x

⇒ x/4 = 2/x

⇒ x² = 8

⇒ x = √8

⇒ x = 2√2

Now we have x, we have the two legs of the right triangle with hypotenuse labelled y.

Using Pythagoras' Theorem a² + b² = c² (where a and b are the legs and c is the hypotenuse)

⇒ 4² + (2√2)² = y²

⇒ y² = 24

⇒ y = √24

⇒ y = 2√6

7 0
2 years ago
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