The answer will be b. membrane.
Answer:
The excess reactant is the NaCl.
Explanation:
NaCl(aq) + AgNO3 (aq) → NaNO₃(aq) + AgCl (s) ↓
This is a precipitation reaction.
We need to convert the mass of each reactant to moles:
4 g / 58.45 g/mol = 0.068 moles of NaCl
10 g / 169.87 g/mol = 0.059 moles of nitrate.
As stoichiometry is 1 by 1, 1 mol of chloride will react with 1 mol of nitrate.
If I have 0.059 moles of nitrate, I will need the same amount of chloride and I have 0.068 moles. I still have chloride, therefore the excess reactant is the NaCl.
0.068 mol - 0.059 mol = 0.009 moles are the moles of NaCl that remains after the reaction is complete
<span>egg, larva, pupa, adult.
If this was the appropriate answer make sure to mark as the brainliest!
-procklown</span>
3 a <span>positively charged nucleus surrounded by negatively charged protons</span>
Answer:
Ni^2+ is most likely
Ti^3+ is very unlikely
Explanation:
The Crystal Field Stabilization Energy almost always favors octahedral over tetrahedral in very many cases, but the degree of this favorability varies with the electronic configuration. In other words, for d1 there is only a small gap between the octahedral and tetrahedral lines, whereas at d3 and d8 is a very big gap. However, for d0, d5 high spin and d10, there is no crystal field stabilization energy difference between octahedral and tetrahedral. The ordering of favorability of octahedral over tetrahedral is:
d3, d8 > d4, d9> d2, d7 > d1, d6 > d0, d5, d10. This explains the answer choices above.
Ti^3+ being a d1 specie is least likely to exist in octahedral shape while Ni2+ a d8 specie is more likely to exist in octahedral shape.