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True [87]
3 years ago
11

Can anyone answer this? (I thank)

Chemistry
1 answer:
Mamont248 [21]3 years ago
4 0
CO2 will be the first to boil because it will be the first to warm up because it is the closest temperature to 0
You might be interested in
Predict the following product(s) of the following reaction? F2 + KCI →
slega [8]

Answer:

{ \rm{F _{2(g)}  + 2KCl _{(aq)}  → { \bold{2KF _{(g)} + Cl_{2(g)} }}}}

Explanation:

» The prediction is 98% correct because single displacement reaction type is highly possible.

This is because Fluorine has is more electronegative than Chlorine in Potassium Chloride. So, it strongly displaces Chlorine from the solution hence forming Chlorine gas.

» The 2% of wrong prediction maybe because of wrong reactant measurements following mole concept chemistry.

If you are asked the observation,

Observation » <u> </u><u>A</u><u> </u><u>green</u><u> </u><u>yellowish</u><u> </u><u>gas</u><u> </u><u>is</u><u> </u><u>formed</u><u>.</u>

This gas is Chlorine gas (Cl2)

5 0
2 years ago
Can someone please answer this question please I really need to know
Zarrin [17]

Answer: aging?

Explanation: sorry, i’m not too sure, but that would be my best guess.

8 0
3 years ago
12
VARVARA [1.3K]

Answer:

B

Explanation:

the number of protons never changes even if the atomic mass changes

5 0
3 years ago
1. A neutral atom of fluorine (F) has 9 electrons and an electron configuration of 1s2 2s2 2p5. How will it ionize to achieve an
Natasha2012 [34]
These answers dont make sense

1. the 2s2 orbital will give one of its electrons to the 2p5 orbital so the configuration would be 1s22s12p6 (2s1 is half filled and 2p6 is completely filled which is a much more stable configuration)

2. Neon does not need to ionize it is a noble gas
4 0
3 years ago
Which of the following equations represent redox reactions? For each redox reaction, determine which atom is oxidized and which
makkiz [27]

Answer:

c. H2(g) + CuO(s) → Cu(s) + H2O(l)

e. H2(g) + Cl2(g) → 2HCl(g)

Explanation:

A redox reaction is a reaction that involves a changes in oxidation number of the species involved in the reaction.

The oxidizing agent experiences a decrease in oxidation number while the reducing agent experiences an increase in oxidation number.

For H2(g) + CuO(s) → Cu(s) + H2O(l)

Copper is reduced from +2 to 0 while hydrogen is oxidized from 0 to +2 Hence hydrogen is the reducing agent while copper is the oxidizing agent.

For H2(g) + Cl2(g) → 2HCl(g)

Chlorine is reduced from 0 to -1 while hydrogen is oxidized from 0 to +1. Hence chlorine is the oxidizing agent while hydrogen is the reducing agent.

4 0
3 years ago
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