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Elena-2011 [213]
3 years ago
13

Synthesize Information In a multistep process, cells can combine the reactants glucose (C6H12O6) and oxygen (O2) to form the pro

ducts carbon dioxide (CO2) and water (H2O). Some cells can also perform the reverse of this process. Must one, both, or neither of the processes release energy? Explain.
Chemistry
1 answer:
zloy xaker [14]3 years ago
8 0

Answer:

Explanation:

In one of the process, energy is built up from scratch, in the other one, energy is liberated for use by an organism or body.

The first process deals with a metabolic reaction in which energy is liberated:

         C₆H₁₂O₆ + 6O₂  → 6CO₂ + 6H₂O + energy

In the above process, energy is liberated when glucose combines with oxygen. The waste products are carbon dioxide and water. This process liberates heat energy which can be used to do work.

   In the reverse process:

             6CO₂ + 6H₂O   →  C₆H₁₂O₆ + 6O₂

    This process stores energy in carbon chains as chemical energy. It is this energy that is released in the first process.

Therefore, we can see that the first process liberates energy and the reverse process stores energy.

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At 1000 K the Kc value for the following reaction is 1.5 × 10⁶ (1) N₂O₄ (g) ⇌ 2 NO₂ (g) At 1000 K the Kc value for the following
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Answer:

The value of Kc is 9.33 * 10^-17

Explanation:

Step 1: Data given

Temperature = 1000 K

N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6

N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g)  Kc = 1.4 * 10^-10

Step 2: Calculate Kc for  N₂ (g) + 2 O₂ ⇌ N₂O₄

N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6

2 NO₂ (g) ⇌  N₂O₄ (g)    = 1/Kc = 1 / 1.5 * 10^6   = 6.67 *10^-7

N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g)  Kc = 1.4 * 10^-10

Kc = Kc1 * Kc2

Kc = (6.67 *10^-7) * (1.4 * 10^-10)

Kc = 9.33 * 10 ^-17

The value of Kc is 9.33 * 10^-17

4 0
3 years ago
How many moles of ammonium nitrate are there in 32.5 mL of<br> a0.125 M NH4NO3 solution?
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<u>Answer:</u> The number of moles of ammonium nitrate is 0.004 moles.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

We are given:

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Volume of solution = 32.5 mL

Putting values in above equation, we get:

0.125M=\frac{\text{Moles of }NH_4NO_3\times 1000}{32.5mL}\\\\\text{Moles of }NH_4NO_3=0.004mol

Hence, the number of moles of ammonium nitrate is 0.004 moles.

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