2 years ago

PLEASE I BEG YOU! Help me !

Mathematics

1 answer:

dlinn [17]2 years ago

3 0

Answer:

MADE IT I WORKED HARD SO MAYBE BRAINLIEST CAN HELP

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$\bold{r+\frac{3Q}h=t}\\-r\qquad\ -r\\\bold{\frac{3Q}h=t-r}\\\cdot h\qquad \cdot h\\ \bold{3Q=(t-r)h}\\^{\div(t-r)\quad\div(t-r)}\\\bold{\dfrac{3Q}{t-r}=h}$

Or, if you mean (r+3Q)/h=t:

$\bold{\frac{r+3Q}h=t}\\{}\ \ \cdot h\quad\ \cdot h\\\bold{r+3Q=ht}\\{}\ \ \div t\qquad \div t\\\bold{\dfrac{r+3Q}{t}=h}\\\\\bold{h=\dfrac{r+3Q}{t}}$

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