PLZZZZ HELP MEEE

A cleaning solution uses 5 cups of soap for every 2 cups of vinegar. If Emery put 4 cups of soap in a container, how

Tasya [4]

1.6 cups of vinegar for 4 cups of soap.

5 0

2 years ago

Jan is the regional manager of Graphic DesignWorks. She uses a company

kogti [31]

Answer:

300

Step-by-step explanation:

If each branch pays the bill equally, and the bill accounts for a year's worth of pay, then you should multiply 125*12~giving you 1500

Then you divide 1500/5, since the 5 company's pay equally... this is equal to 300 dollars.

8 0

2 years ago

Read 2 more answers

First one to answer receives 100 points and brainiest!

larisa [96]

Answer and Step-by-step explanation:

116 b.

$2^{10} = 1024\\2^8 = 256\\\\1024 + 256 = 1280\\\\\\2^5 = 32\\2^3 = 8\\\\32 - 8 = 24$

1280 × 24 = 30720

30720 ÷ 60 = 512. 512 is the solution; the expression is divisible by 60.

116 c.

$16^3 = 4096\\8^3 = 512\\\\4096 - 512 = 3584\\\\\\4^3 = 64\\2^3 = 8\\\\64 + 8 = 72$

3584 × 72 = 258048

258048 ÷ 60 = 4096. 4096 is the solution; the expression is divisible by 63.

116 d.

$125^2 = 15625\\25^2 = 625\\\\15625 + 625 = 16250\\\\\\5^2 = 25\\\\25 - 1 = 24$

16250 × 24 = 390000

390,000 ÷ 39 = 10,000. 10,000 is the solution; the expression is divisible by 39.

#teamtrees #PAW (Plant And Water)

4 0

3 years ago

One side of a rectangle is 10 feet shorter than twice another side. Find the length of the shorter side if we also know the peri

seropon [69]

Answer:

6 feet

Step-by-step explanation:

Let x represent the length of "another side." Then "one side" is ...

2x -10 . . . . . . 10 feet shorter than twice another side

The sum of these two side lengths is half the perimeter, so is ...

x + (2x -10) = 14 . . . . . two sides are half the perimeter

3x = 24 . . . . . . . . . . . . add 10, collect terms

x = 8 . . . . . . . . . . . . . . .divide by the coefficient of x

(2x -10) = 2·8 -10 = 6 . . . . find "one side"

We have found "one side" to be 6 feet long, and "another side" to be 8 feet long. The shorter side is 6 feet.

8 0

2 years ago

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago