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3 years ago

The least. Common multiple for 8 19 and 23

Mathematics

1 answer:

jenyasd209 [6]3 years ago

3 0

<h2><em>Answer:</em></h2>

The least common multiple for 8, 19, 23 would be 3496

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Solve for x in the diagram below

MrRissso [65]

Answer:

x=20 degrees

Step-by-step explanation:

because this is a supplementary angle, you add everything and set it equal to 180 degrees. so it would be x + 100 + 3x = 180. combine like terms to get 100 + 4x = 180. subtract 100 from both sides to get 4x = 80. divide by 4 on both sides to isolate the x and your final answer is 20. hope this helped! good luck in school xoxo

8 0

3 years ago

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

7 0

3 years ago

I have 30 points to give away. One person answers this question and takes 10 points. If another person takes 10 more points, how

Ghella [55]

Answer:

10 points

Step-by-step explanation:

plz brainleist

8 0

3 years ago

What is the distance between the points? Round to the nearest tenth if necessary.

Svetlanka [38]

Answer:

1.7

Step-by-step explanation:

You do rise over run or y/x to find your answer. You go over 6 and up 10 to get from the lower point to the one on top. 10/6=1.666667 and rounded will be 1.7

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2 years ago

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The regular hexagon below is centered at the origin. It is rotated clockwise around the origin through an angle of k° For which

tatiyna

Option D is correct hope i helped at all

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3 years ago

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