Where is it? Don’t see it so uh
To write a ratio as a fraction, we simply take the first number in the ratio and make it the numerator while taking the second number in the ratio and making it the denominator.
Because we want the ratio of engines to box cars, our ratio should be:
number of engines/number of box cars
When we substitute in our respective values, we get:
4/18
To simplify this ratio, we have to find the GCF, or greatest common factor of the numerator and the denominator, which in this case is 2. To simplify, we divide both the numerator and the denominator by the GCF, as follows:
4/2 / 18/2
When we simplify, we get:
2/9
Therefore, your answer is 2/9.
Hope this helps!
Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
Answer:
The brother would be 13
Step-by-step explanation:
14 - 6= 8
There's an 8-year difference
21 - 8= 13
