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Oksanka [162]
3 years ago
8

1. Jose and Carlos received P 450 as prize for

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
8 0

Answer:

1.Jose received 5/9×P450=P250

2.A dozen =12

12/3=4×165=660

3.40/1002/5

4. 100/60×9=15

5. 60/100×40=24

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Find three consecutive intergers such that three times the third is 102 more than the sum of the first and second.
Pavlova-9 [17]

Answer:

A) x + x+1 + x+2

We don't need equation A)

B) 3*(x+2) = (x + X+1) +102

3x + 6 = 2x + 1 + 102

x = 97

Numbers are 97, 98 and 99

Step-by-step explanation:

6 0
4 years ago
Delta math: Angle Terminology with Equations
DaniilM [7]

Answer:

m∠A = 139°

Step-by-step explanation:

First we must know that

Supplementary angles equal to 180 degree.

Since we know that supplementary angles equal to 180 degree we can solve now:

Putting m ∠A and m ∠ B together and put the = 180

( 7x - 15 ) + ( 2x - 3 ) = 180

Now solving for x:

( 7x - 15 ) + ( 2x - 3 ) = 180

9x - 18 = 180

9x - 18 + 18 = 180 + 18

9x  = 198

9x/9 = 198/9

x = 22

Hence,  Angle A will have a measure of 7x - 15 which means  7 ×  22 -15 = 154 - 15 = 139°

m∠A = 139°

The measure of Angle B will be 2x - 3 = 2 • 22 - 3 = 44 - 3 = 41°

m∠ B = 41°

139 + 31= 180

<u><em>[RevyBreeze]</em></u>

3 0
3 years ago
6+y= -3<br> what’s the answer
erma4kov [3.2K]

Answer:

y=-9

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Giving 100 points.
Nitella [24]

Answer:

1.   <u>Cost per customer</u>:  10 + x

     <u>Average number of customers</u>:  16 - 2x

\textsf{2.} \quad  -2x^2-4x+160\geq 130

3.    $10, $11, $12 and $13

Step-by-step explanation:

<u>Given information</u>:

  • $10 = cost of buffet per customer
  • 16 customers choose the buffet per hour
  • Every $1 increase in the cost of the buffet = loss of 2 customers per hour
  • $130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

<u>Part 1</u>

<u></u>

<u>Cost per customer</u>:  10 + x

<u>Average number of customers</u>:  16 - 2x

<u>Part 2</u>

The cost per customer multiplied by the number of customers needs to be <u>at least</u> $130.  Therefore, we can use the expressions found in part 1 to write the <u>inequality</u>:

(10 + x)(16 - 2x)\geq  130

\implies 160-20x+16x-2x^2\geq 130

\implies -2x^2-4x+160\geq 130

<u>Part 3</u>

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

\implies -2x^2-4x+160\geq 130

\implies -2x^2-4x+30\geq 0

\implies -2(x^2+2x-15)\geq 0

\implies x^2+2x-15\leq  0

\implies (x-3)(x+5)\leq  0

Find the roots by equating to zero:

\implies (x-3)(x+5)=0

x-3=0 \implies x=3

x+5=0 \implies x=-5

Therefore, the roots are x = 3 and x = -5.

<u>Test the roots</u> by choosing a value between the roots and substituting it into the original inequality:

\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144

As 144 ≥ 130, the <u>solution</u> to the inequality is <u>between the roots</u>:  

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.  

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an <em>increase </em>in cost.  It does not confirm that if the cost is reduced (less than $10) the number of customers <em>increases </em>per hour.]

<u>Cost per customer</u>:  

x =0 \implies 10 + 0=\$10

x=3 \implies 10+3=\$13

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0
2 years ago
What is the ratio of the number of cans to the price 24 <a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail=
Marta_Voda [28]
2 : 9
multiply each by 12 because 24 ÷ 2 = 12
so
24 : 108
but when simplified is 2 : 9
7 0
4 years ago
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