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Lady bird [3.3K]
3 years ago
10

What combination of transformations is shown below?

Mathematics
1 answer:
scoray [572]3 years ago
7 0

Answer:

Correct answer is <em>"reflection, then rotation".</em>

Step-by-step explanation:

The figure shows the following two operations:

1) Reflection through central horizontal line. (1 \to 2)

2) Rotation with center at the upper left corner of the reflected figure. (2 \to 3)

Therefore, correct answer is <em>"reflection, then rotation".</em>

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Answer:

15 units

Step-by-step explanation:

8 0
3 years ago
1. Sally said that when you add or subtract positive or negative decimals, you can change the order of the decimals and still ge
siniylev [52]
Always true because addition and subtraction is commutative
-6.2-(-3.96) = -2.24
-3.96-(-6.2)= -2.24
5.71+2.84=8.55
2.84+5.71=8.55  
Hope this helped :)
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3 years ago
Which is the value of 3b2−b3b2-b when b = 5?
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What's the equation exactly?

8 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (-3,1) and (7,-14)
Katyanochek1 [597]

Answer:

-  \frac{3}{2}

Step-by-step explanation:

\boxed{gradient =  \frac{y1 - y2}{x1 - x2} }

Using the formula above,

slope of line

=  \frac{1 - ( - 14)}{ - 3 - 7}  \\  =  \frac{1 + 14}{ - 10}  \\  =  \frac{15}{ - 10}  \\  =  -  \frac{3}{2}

5 0
3 years ago
Solve the equation. And write all solutions in general form.
Amiraneli [1.4K]

Answer:

x = pi/2 + 2 pi n                            x = pi + 2 pi n   where n is an integer

x = 5pi /3 + 2 pi n                      

Step-by-step explanation:

8 cos^2 x + 4 cos x-4 = 0

Divide by 4

2 cos^2 x +  cos x-1 = 0

Let u = cos x

2 u^2 +u -1 =0

Factor

(2u -1) ( u+1) = 0

Using the zero product property

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u = 1/2      u = -1

Substitute cosx for u

cos x = 1/2    cos x = -1

Take the inverse cos on each side

cos ^-1(cos x) = cos ^-1(1/2)   cos ^-1( cos x) =cos ^-1( -1)

x = pi/2 + 2 pi n                            x = pi + 2 pi n   where n is an integer

x = 5pi /3 + 2 pi n                      

8 0
3 years ago
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