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crimeas [40]
3 years ago
11

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Chemistry
2 answers:
cricket20 [7]3 years ago
7 0

Answer:hi

Explanation: .

professor190 [17]3 years ago
5 0
And 90% of people marry there 7th grade love. since u have read this, u will be told good news 2night. if u don't pass this on nine comments ur worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of ur life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love u
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Each incomplete reaction is a neutralization reaction Match each equation with the salt formed,
Sonbull [250]

Answer: 2hqu

Explanation: because you have to add them

6 0
3 years ago
Read 2 more answers
The equilibrium constant, K., for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC13(E) Calculate the equilibrium
lord [1]

Answer:

The equilibrium concentration of PCl_5=0.228 M.

The equilibrium concentration of PCl_3=0.280 M -0.228 M=0.052M.

The equilibrium concentration of Cl_2=0.280 M -0.228 M=0.052M.

Explanation:

Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = K_c=83.3

Moles of PCl_3 = 0.280 mol

Concentration of  [PCl_3]=\frac{0.280 mol}{1.00 L}=0.280 M

Moles of Cl_ = 0.280 mol

Concentration of [Cl_2]=\frac{0.280 mol}{1.00 L}=0.280M

           PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

Initial:            0.280      0.280                            0

At eq'm:         (0.280-x)   (0.280-x)                     x

We are given:

[PCl_3]_{eq}=(0.280-x)

[Cl_2]_{eq}=(0.280-x)

[PCl_5]_{eq}=x

Calculating for 'x'. we get:

The expression of K_{c} for above reaction follows:

K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}

Putting values in above equation, we get:

83.3=\frac{x}{(0.280-x)\times (0.280-x)}

On solving this quadratic equation we get:

x = 0.228, 0.344

0.228 M < 0.280 M< 0.344 M

x = 0.228 M

The equilibrium concentration of PCl_5=0.228 M.

The equilibrium concentration of PCl_3=0.280 M -0.228 M=0.052M.

The equilibrium concentration of Cl_2=0.280 M -0.228 M=0.052M.

4 0
3 years ago
What is the mass of 0.500 moles of chlorine gas?
emmainna [20.7K]

Answer: m = 17.5 g Cl

Explanation: To find the mass of Cl we will need to convert the moles of Cl to mass using the relationship of 1 mole = molar mass of Cl.

0.500 mole Cl x 35 g Cl / 1 mole Cl

= 17. 5 g Cl

8 0
3 years ago
Use each of the following reaction quotients to write the balanced equation:(b) Q = [NH₃]⁴[O₂]⁷ / [NO₂]⁴[H₂O]⁶
ira [324]

4NH₃(g) + 3O₂(g) ⇄ 2N₂(g) + 6H₂O(g) is the balanced equation.

<h3>What is balanced equation?</h3>

If both the reactants and the products have the same number of atoms and total charge in each component of the equation, the equation describing the chemical reaction is said to be balanced. In other words, the mass and charge in the reaction are equal on both sides.

A chemical equation is the symbolic representation of a chemical reaction in the form of symbols and formulae, where the reactant entities are given on the left and the product entities on the right, with a plus sign between the entities in both the reactants and the products and an arrow that points towards the products, showing the direction of the reaction.

To learn more about balanced equation from the given link:

brainly.com/question/28297774

#SPJ4

7 0
2 years ago
IPSPs (inhibitory postsynaptic potentials) a. block the efflux of potassium ions. b. are local hyperpolarizations. c. are local
Likurg_2 [28]

IPSPs are local hyperpolarizations.

Option B

<u>Explanation:</u>

The Inhibitory Post Synaptic Potentials are basically resultant of local hyper polarization and by then they degrade to depolarization. These are synaptic potentials which causes the neuron of post synapse to engage in lesser generation of action potential.

The local hyper polarization is achieved as the post synapse membrane has the negative potential more than that of resting membrane, then the condition becomes hyper polarization. In order to achieve so, the action potential must under go depolarization and hence it degrades to depolarization.

5 0
3 years ago
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