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3 years ago

Why is the r.a.m. Value used?

Chemistry

1 answer:

Andrew [12]3 years ago

5 0

Answer:

The r.a.m. value is used to determine how many isotopes an element has.

Explanation:

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What are fossil fuels made from

TiliK225 [7]

Answer:

Coal, crude oil, and natural gas are all considered fossil fuels because they were formed from the fossilized, buried remains of plants and animals that lived millions of years ago. Because of their origins, fossil fuels have a high carbon content.

Explanation:

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3 years ago

Beer's Law states that A=ebc, where A is the absorbance, ε is the molar absorptivity of the solute, b is the path length, and c

Gelneren [198K]

Answer:

b. changing the compound changes the absorbance behavior.

Explanation:

Option a) would be akin to modifying the path length, b.

Option b) would involve using a different solute, as such, there would be another molar absortivity, ε.

Option c) would decrease the concentration (c) of the solute, which would explain why the absorbance would decrease as well.

8 0

3 years ago

A solution of salt water is boiled. The water evaporates and solid salt remains. Which statement is true?

Scorpion4ik [409]

C because neither the water or salt have changed their molecular structure. H2O is still H2O and NaCl is still NaCl.

4 0

4 years ago

Nulceic acids are assorted with the cell memebrane true or false

Sauron [17]

Answer:

false should be the correct response.

8 0

3 years ago

Calculate the weight percent of ascorbic acid in a tablet of Vitamin C from the following data:A 80 mg sample of a crushed Vitam

Lina20 [59]

Answer:

The Answer is 88%

Explanation:

The balanced ionic equation of the reaction

$IO^{3- }+ 8 I^- + 6 H^+ => 3 I^{3- }+ 3 H_2O$

$I^{3-} + 2 S_2O_3^{2-} => 3 I^- + S_4O_6^{2-}$

$C_6H_8O_6 + I^{3- }+ H_2O => C_6H_6O_6 + 3 I^- + 2 H^+$

Looking at the above reactions

The original number of moles of $I^{3-}$ = 3 × number of moles of $IO^{3-}$

= 3 × volume × concentration of $KIO_3$

Note: The formula for number of moles is volume × concentration

$=3 * \frac{40}{1000} * 0.00653 =0.000784$ mol

The number of moles of $I^{3-}$ left after its reaction with ascorbic acid

= $\frac{1}{2}$ x moles of $S_2O_3^{2-}$

= $\frac{1}{2}$ x volume x concentration of $S_2O_3^{2-}$

$= \frac{1}{2} * \frac{15}{1000} * 0.0510 =0.000383 \ mol$

Note: The division by 1000 is to convert mill liter to liter

Moles of ascorbic acid = moles of $I^{3-}$ reacted

$= initial \ moles \ of \ I^{3-} \ - remaining \ moles \ of \ I^{3-}$

$=0.000784 - 0.000383$

$=0.000401 \ mols$

$Mass = moles \ * molar \ mass$

Hence

Mass of ascorbic acid = moles of ascorbic acid × molar mass of ascorbic acid

$= 0.000401* 176.12 = 0.07055\ g$

$= 70.55\ mg$

Weight% of ascorbic acid = mass of ascorbic acid/mass of sample x 100%

= 70.55/80 × 100%

= 88.1%

3 0

4 years ago