The company installs 5000 light bulbs with an average of 500 hours for each bulb. The standard deviation of 100 hours and distribution approximated by a normal curve. The percentage of bulbs that can be expected to last the period of time of less than 690 hours is 97.1%. This will make the answer to be C.
100•-4=-400 -400•40=-16000
Answer:
2n(8n + 5)
Step-by-step explanation:
you need to see what you can take out of both the numbers.
ex they both have an 'n' and they both are divisible by 2
1 gallon is 16 cups
we have 11/4 cups which multiplied by 16 gives us 44 cups
