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3 years ago

The list below shows the different taco shells, fillings, and toppings sold at Rico's Taco Bar.

Mathematics

1 answer:

Pepsi [2]3 years ago

7 0

Answer:

30 different types of tacos can Rico make.

Step-by-step explanation:

Given - The list below shows the different taco shells, fillings, and toppings sold at Rico's Taco Bar.

Taco Shells Fillings Toppings

Soft Chicken Cheese

Hard Beef Lettuce

Bean Sour Cream

Onions

Salsa

To find - How many different types of tacos can Rico make using one taco shell, one filling, and one topping?

Proof -

Given that,

There are 2 different types of Taco shells, 3 different type of fillings and 5 different types of toppings.

So, by the fundamental principal of counting,

Total types of tacos Rico made = 2 × 3 ×5 = 30

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Answer:

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Which of the following is the solution of 5x – 6 = 44?

nata0808 [166]

Answer:

x = 10

Step-by-step explanation:

5x - 6 = 44

Add 6 on both sides of the equation.

5x = 50

Divide by 5 on both sides of the equation.

x = 10

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3 years ago

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If f(x)=7x-3, what is the value of x when f(x)=1

frosja888 [35]

Set up your equation:
1 = 7x - 3

Add 3 to both sides:
7x = 4

Divide both sides by 7:
x = 4/7

Hope this helps!

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2 years ago

Carina begins to solve the equation -4 - 2/3x = -6 by adding 4 to both sides. Which statements regarding the rest of the solving

Andru [333]

Answer:

A.) After adding 4 to both sides, the equation is $-\frac{2}{3}x=-2$

C.) The equation can be solved for x using exactly one more step by multiplying both sides by $-\frac{3}{2}$

D.) The equation can be solved for x using exactly one more step by dividing both sides by $-\frac{2}{3}$

Step-by-step explanation:

The correct questions is as follows:

Carina begins to solve the equation -4-2/3x=-6 by adding 4 to both sides. Which statements regarding the rest of the solving process could be true? Check all that apply.

A.) After adding 4 to both sides, the equation is -2/3x=-2.

B.) After adding 4 to both sides, the equation is -2/3x=-10 .

C.) The equation can be solved for x using exactly one more step by multiplying both sides by -3/2.

D.) The equation can be solved for x using exactly one more step by dividing both sides by -2/3.

E.) The equation can be solved for x using exactly one more step by multiplying both sides by -2/3.

Given equation:

$-4-\frac{2}{3}x=-6$

To show the steps we will carry out in order to solve for $x$

Solution:

Solving for $x$

Step 1:

Adding both sides by 4

$4-4-\frac{2}{3}x=-6+4$

Thus, we get:

$-\frac{2}{3}x=-2$

Thus statement A is correct.

Step 2:

Multiplying both sides by $-\frac{3}{2}$

$-\frac{3}{2}\times -\frac{2}{3}x=-2\times -\frac{3}{2}$

Thus, we get:

$x=3$ [Two negatives multiply to give a positive]

This proves that statement C is correct.

Or Step 2:

Dividing both sides by $-\frac{2}{3}$

$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{-2}{-\frac{2}{3}}$

Thus, we get:

$x=-2\times -\frac{3}{2}$ [On dividing with a fractional divisor, we take reciprocal and multiply it with the dividend.]

$x=3$ [Two negatives multiply to give a positive]

This prove that statement D is correct.

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3 years ago

I need help with all of them and if you can't help with all of them just answer one of them please. Look at the picture

likoan [24]

All you have to do is substitute the y value from the 1st equation into the second equation and solve...

a) y= 2-x
5x + 4y = 5

Substitute (2-x) into the second equation anywhere there is a y...

5x + 4y = 5
5x + 4(2-x) = 5

Now solve

5x + 8 - 4x = 5
5x - 4x + 8 = 5
x + 8 = 5
x = -3

Now that you have a solution for x, substitute -3 into either of the original equations anywhere there is an x then solve for y...

y = 2 - x
y = 2 - (-3)
y = 2+3 = 5

You solved for x and got -3 and solved for y and got 5, so your solution set is
(-3, 5).

Now check it by substituting both numbers into one of the original equations and you should have a true statement if it is correct...

y = 2 - x
5 = 2 - (-3)
5 = 2+3
5 = 5

True statement... it checks!

note* during the check, if the equation would have worked out to something like 2 = 5, then that is a false statement therefore the solution set would be wrong and you'd have to go back and find the mistake.

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3 years ago