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butalik [34]
3 years ago
5

PLS HELP ME!!!!!!!!!!! Satish's register shows a deposit on February 4 in the amount of $150.00, an atm withdrawal on February 5

in the amount of $180, and another deposit on February 7 in the amount of $225.56. What should Satish's balance in his register be? A. $610.82, B.$792.91, C.$910.82, or D.$947.14
Mathematics
2 answers:
RoseWind [281]3 years ago
8 0

Answer: C. 910.82

Step-by-step explanation: if you add

195.56 for 715.26 you got 910.82 it’s more easier how to do it :3 I hope it’s help!!

7nadin3 [17]3 years ago
5 0

Answer:

Balance = $195.56

Step-by-step explanation:

Credit:

Feb 4 deposit = $150.00

Feb 7 deposit = $225.56

Total credit = $375.56

Debit:

Feb 5 ATM withdrawal = $180

Total Debit = $180

Balance = credit - debit

= $375.56 - $180

= $195.56

Balance = $195.56

The answer is not included in the option. It is either the options are not correct or the values in the question are not correct. Please recheck

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The length of a rectangle is 5.2cm and its breadth is 3.4cm. What is the area of the rectangle?
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Answer:

\huge{ \boxed{ \sf{17.68 \:  {cm}^{2} }}}

Step-by-step explanation:

\underline{ \text{Given}} :

\longrightarrow \sf{ \: Length \: of \: a \: rectangle \:  =  \: 5.2 \: cm}

\longrightarrow{ \sf{Breadth \: of \:  \: rectangle \:  =  \: 3.4 \: cm}}

\underline{ \text{To \: find} } :   \sf{Area \: of \: a \: rectangle}

\boxed{ \sf{Area \: of \: a \: rectangle \:  =  \: Length \:  \times  \: Breadth}}

\mapsto{ \sf{Area \:  =  \: 5.2 \: cm \:  \times  \: 3.4 \: cm}}

\mapsto{ \sf{Area \:  =  \: 17.68 \:  {cm}^{2} }}

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3 years ago
Solve this problem using the substitution method 2y-1/2y=2
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Answer:

y=3/2and x =2

Step-by-step explanation:

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There is a free prize drawing in a shopping mall. There are some youngsters and older people. The result of the number of winnin
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Answer:

There is a free prize drawing in a shopping mall. There are some youngsters and older peoples. The result of the number of winning people is shown below.

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When a gas is kept at a constant temperature and pressure on it changes, its volume changes according to the following formula,
astra-53 [7]

Answer:  Approximately 1.9 atm

============================================

Work Shown:

P_1*V_1 = P_2*V_2 \ \text{ ... Boyle's Law}\\\\4.5*1.5 = P_2*3.5\\\\6.75 = P_2*3.5\\\\P_2*3.5 = 6.75\\\\P_2 = \frac{6.75}{3.5}\\\\P_2 \approx 1.92857142857142\\\\P_2 \approx 1.9\\\\

If the volume is 3.5 liters, then the pressure is approximately 1.9 atm.

Note the increase in volume leads to the reduction of pressure, and vice versa. The two variables have an inverse relationship.

-----------

As a check,

P_1*V_1 = P_2*V_2\\\\4.5*1.5 \approx 1.9*3.5\\\\6.75 \approx 6.65\\\\

We don't get the exact thing on both sides, but the two sides are close enough. We have rounding error due to P2 being not exact.

A more accurate check could be

P_1*V_1 = P_2*V_2\\\\4.5*1.5 \approx 1.92857*3.5\\\\6.75 \approx 6.749995\\\\

which has the two sides much closer to one another. This helps us verify the answer.

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3 years ago
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