we can always find the x-intercept by simply settting y = 0, and solving for "x".
and we can always find the y-intercept by simply setting x = 0 and solving for "y".
![\bf x-4y=-16\implies \stackrel{x=0}{0-4y=-16}\implies y=\cfrac{-16}{-4}\implies y=4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (0,4)~\hfill](https://tex.z-dn.net/?f=%20%5Cbf%20x-4y%3D-16%5Cimplies%20%5Cstackrel%7Bx%3D0%7D%7B0-4y%3D-16%7D%5Cimplies%20y%3D%5Ccfrac%7B-16%7D%7B-4%7D%5Cimplies%20y%3D4%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A~%5Chfill%20%280%2C4%29~%5Chfill%20)
17.9/2.38
= 7.5.
Hope this helps & good luck. :)
Since the discriminant given has a value that is greater than zero, hence the roots of the quadratic equation are real and distinct.
<h3>Discriminant of a quadratic equation</h3>
Quadratic equation is an equation that has a leading degree of 2. The discriminant is used to determine the nature of the equation
If D > 0 , the roots of the quadratic equation are real and distinct.
If D < 0 , the roots of the quadratic equation are complex
Since the discriminant given has a value that is greater than zero, hence the roots of the quadratic equation are real and distinct.
Learn more on discriminant here: brainly.com/question/2507588
#SPJ1
Answer:
y=-x-5
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-8-(-1))/(3-(-4))
m=(-8+1)/(3+4)
m=-7/7
m=-1
y-y1=m(x-x1)
y-(-1)=-1(x-(-4))
y+1=-1(x+4)
y+1=-x-4
y=-x-4-1
y=-x-5
Please mark me as Brainliest if you're satisfied with the answer.
It has all angles measuring 60°
