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2 years ago

PLEASE PLEASE HELP PLEASEEEEEEEEEEEEEEE

Mathematics

2 answers:

Mamont248 [21]2 years ago

5 0

Answer:

Six less than five times a number is less than fourteen

Step-by-step explanation:

I had the same question on my homework haha

denis-greek [22]2 years ago

3 0

X is greater than 4

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7th grade math help me plzzz

sp2606 [1]

Answer:

4 + (-10)

Step-by-step explanation:

for the answer you are taking adding TEN negatives from a non negative number. So we subtract 4 - 10 this equals -6 which is the same as -10 - (-4)

4 0

2 years ago

If I read 2/3 of a book that has 222 pages how many pages do I have left to read

joja [24]

Multiply 2/3 by 222 then subtract the number from 222 and you should get your answer

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2 years ago

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I need help with this math problem. Please someone help me if they can.

Veronika [31]

The answer is <span>412

hope this helps
can i plz get brainliest </span>

6 0

2 years ago

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7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

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3 years ago

What is the area of the triangle in cm?

LekaFEV [45]

Answer:

Step-by-step explanation:

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2 years ago

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