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3 years ago

WILL GIVE BRAINLIEST IMMEDIATELY!!! INSTANT BRAINLY!! PLS HELP

Mathematics

1 answer:

lys-0071 [83]3 years ago

5 0

Answer:

The two column proof is presented as follows;

Statement ${}$ Reason

1. Parallelogram SUPN $\overline {SR}$ ⊥ $\overline {UN}$ ${}$ 1. Given

and $\overline {MP}$ ⊥ $\overline {UN}$

2. ∠SRU = ∠PMN = 90° ${}$ 2. Definition of perpendicular lines

3. ∠SRU ≅ ∠PMN ${}$ 2. Definition of congruency

4. $\overline {UP}$ ║ $\overline {SN}$ ${}$ 4. Opposite sides of a parallelogram are ${}$ congruent

5. ∠SNR ≅ ∠PUM ${}$ 5. Alternate interior angles are congruent

6. $\overline {UP}$ ≅ $\overline {SN}$ ${}$ 6. Opposite sides of a parallelogram are ${}$ congruent

7. ΔPMU ≅ ΔSRN ${}$ 7. By AAS rule of congruency

By the Angle-Angle-Side (AAS) rule of congruency, we have that, if two angles and a corresponding adjacent side (∠SRU ≅ ∠PMN, ∠SNR ≅ ∠PUM, $\overline {UP}$ ≅ $\overline {SN}$ ) of two triangles (ΔPMU and ΔSRN) are congruent, then the the two triangles are also congruent (ΔPMU ≅ ΔSRN)

Step-by-step explanation:

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It has been hypothesized that the standard deviation of the germination time of radish seeds is 8 days. The standard deviation o

Yanka [14]

Answer:

$\chi^2 =\frac{60-1}{64} 36 =33.19$

The degrees of freedom are:

$df= n-1= 60-1= 59$

And the p value would be given by:

$p_v =2*P(\chi^2 >33.19)=0.0053$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true deviation is different from 8 days.

Step-by-step explanation:

Data given

$n=60$ represent the sample size

$\alpha=0.01$ represent the confidence level

$s^2 =6^2 =36$ represent the sample variance obtained

$\sigma^2_0 =8^=64$ represent the value that we want to test

Hypothesis to test

We want to verify if the true deviation is equal to 8 days o not, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 64$

Alternative hypothesis: $\sigma^2 \neq 64$

The statistic is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

Replacing we got:

$\chi^2 =\frac{60-1}{64} 36 =33.19$

The degrees of freedom are:

$df= n-1= 60-1= 59$

And the p value would be given by:

$p_v =2*P(\chi^2 >33.19)=0.0053$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true deviation is different from 8 days.

6 0

4 years ago

The measure of the angle

miv72 [106K]

First, we know this diagram consists of two horizontal lines cut by a transversal line. Therefore, we know that the given angle that measures 113° and the angle we want to find are alternate interior angles. Since all alternate interior angles are equal, we know the unknown angle must also be 113°.

I hope this helps.

5 0

3 years ago

Read 2 more answers

Add (8b - 7) + (6b + 8) simplify the answers. Pls show steps

katovenus [111]

I’m not rlly sure if i did it right & i’m sorry if i didn’t. i used the FOIL method
f= first to first
o=outer to outer
i=inner to inner
l= last to last
so it’d be
8b + 6b = 14b (f)
8b+ 8=16b(o)
-7+6b=-1b(i)
-7+8(l)
and then you add like terms so
[14b+16b-1b]+1
= 29b+1

7 0

3 years ago

Julianna has 32 pieces of candy in a jar. Julianna only has 2 kinds of candy, jolly ranchers and Twix. For every 4 Twix bars, sh

nexus9112 [7]

Answer:

the data set seems wrong, since for every 4twix bars, she had 2 pieces of jolly ranchers; so ratio 4 twix bars : 2 ranchers is to be use but it wouldn't work, it can only work for the first 30 candies ( 20twix bars and 10 ranchers) so the last 2 candies( if following the ratio will be 4/3 for the twix bars and 2/3 for the ranchers)

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3 years ago

Simplify and write the trigonometric expression in terms of sine and cosine:

asambeis [7]

Answer:

we have the expression as;

1/sin u cos u

Step-by-step explanation:

tan u = sin u/cos u

cot u = cos u/sin u

Thus;

sin u/cos u + cos u/sin u

The lcm is sin u cos u

Thus, we have that;

(sin^2 u + cos^2 u)/sin u cos u

But ; sin^2 u + cos^2 u = 1

so we have ;

1/sin u cos u

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3 years ago