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3 years ago

Rewrite the following equation into slope intercept form 3x - 4y = 20 and identify the slope and y - intercept.

Mathematics

2 answers:

Vladimir [108]3 years ago

8 0

You solve for y and get
y=3/4x-5
Slope is 3/4
Y intercept is -5

allochka39001 [22]3 years ago

7 0

Y=3/4x+20 slope=3/4 y intercept= 20

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HELP AGAIN PLEASE I TRIED IT ON MY OWN AND FAILED :(

Alex787 [66]

Answer: ∠ J = 62° , ∠ K = 59° , ∠ L = 59°

<u>Step-by-step explanation:</u>

It is given that it is an Isosceles Triangle, where L J ≅ K J

It follows that ∠ K ≅ ∠ L

⇒ 5x + 24 = 4x + 31

⇒ x + 24 = 31

⇒ x = 7

Input the x-value into either equation to solve for ∠ K & ∠ L:

∠ K = 5x + 24

= 5(7) + 24

= 35 + 24

= 59

∠ K ≅ ∠ L ⇒ ∠ L = 59

Next, find the value of ∠ J:

∠ J + ∠ K + ∠ L = 180 Triangle Sum Theorem

∠ J + 59 + 59 = 180

∠ J + 118 = 180

∠ J = 62

8 0

3 years ago

Simone paid $13 for an initial year's subscription to a magazine. The renewal rate is $8 per year. This situation can be represe

elixir [45]

Data Input

Simone paid $13 for an initial year's

The renewal rate is $8 per year

Equation

y = 8x + 13

Table

x (number of years renewed) | (total cost in dollars)

0 -> 13 dollars

1 -> 21 dollars

2 -> 29 dollars

3 -> 37 dollars

4 -> 45 dollars

7 0

1 year ago

You go to see family in another city. So far you have gone 120 miles. The total trip is 360 miles. What fraction of the total tr

beks73 [17]

1/3 of the total trip has been traveled.

8 0

4 years ago

Read 2 more answers

[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6

viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

Height (in inches) of a 25 year old man is a normal random variable with mean $g=71$ and variance $o^{2} =6.25$ .

To find: (a) What percentage of 25 year old men are 6 feet, 2 inches tall

(b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X> $74in$ ]

P[X>74] = P[ $\frac{X-g}{o}$ > $\frac{74-71}{2.5}$ ]

= P[Z > 1.2]

= 1 - P[Z ≤ 1.2]

= 1 - Ф (1.2)

= 1 - 0.8849

= 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, $6ft$ $5in$ - X, $6ft$ ]

P[X > $6ft$ $5in$ I X > $6ft$ ] = P[X > 77 I X > 72]

= $\frac{P[X > 77]}{P[ X > 72]}$

= $\frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}] }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }$

= $\frac{P[Z >2.4]}{P[Z>0.4]}$

= $\frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }$

= $\frac{1-0.9918}{1-0.6554}$

= $\frac{0.0082}{0.3446}$

= 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0

4 years ago

Lyle and his study team are designing spinners.

RUDIKE [14]

A) 7 SECTION ARE IN GREEN

B)16 HAVE STRIPES

5 0

4 years ago