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sveta [45]
3 years ago
9

Which conversion factor should be used to solve the following problem?

Chemistry
1 answer:
sp2606 [1]3 years ago
3 0

Answer:

2 moles of H₂O / 2 moles of HCl.

Explanation:

The balanced equation for the reaction is given below:

Ca(OH)₂ + 2HCl —> CaCl₂ + 2H₂O

From the balanced equation above,

2 moles of HCl reacted to produce 2 moles of H₂O.

Next, we shall determine number of mole of H₂O produced by the reaction of 3.25 moles of HCl. This can be obtained as follow:

From the balanced equation above,

2 moles of HCl reacted to produce 2 moles of H₂O.

Therefore, 3.25 moles of HCl will react to produce = 3.25 moles of HCl × 2 moles of H₂O / 2 moles of HCl.

Thus, the conversion scale is:

3.25 moles of HCl × 2 moles of H₂O / 2 moles of HCl.

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Answer:The metal complex formed would have the following formula [Cr(NO₂)₆]³⁻. The complex has a net negative charge and hence it can only be isolated as a salt with a positive cation so the formed complex could be isolated as potassium salt. The formula for salt would be K₃[Cr(NO₂)₆].

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The metal ion given to us is Cr³⁺ (Chromium) in +3 oxidation state.

The electronic configuration for the metal ion is  [Ar]3d³ so there are vacant 3d metal orbitals  which are available and hence 6 NO₂⁻ ligands can easily attack the metal center and form a metal complex.

The charge on the overall complex can be calculated using the oxidation states of metal and ligand which is provided.  

The (chromium ) Cr³⁺ metal has +3 charge and 6 NO₂⁻ (nitro) ligands have -6 charge and since  the ligands will be  providing a total of 6 - (negative) charge  and hence only 3- (negative ) charge can be neutralized so a net 3- negative charge would be present on the overall complex which is basically present at the metal center :

charge on the complex=+3-6=-3

Let X be the Oxidation state of Cr in complex =[Cr(NO₂)₆]³⁻

                                                          X-6=-3

                                                           X=-3+6

                                                            X=+3

so our calculated oxidation state of Cr is +3 which matches with the provided in question.

As we can see that the overall metal complex has a net negative charge and hence and only positively charged  cations can form a salt with this metal complex and hence only potassium K⁺ ions can form salt with the metal complex.

since overall charge present on the metal complex is -3 so 3 K⁺ ion would be needed to neutralize it and hence the formula of the metal salt would be K₃[Cr(NO₂)₆].

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