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3 years ago

15

Merits of modern periodic table?

1 answer:

ANEK [815]3 years ago

6 0

Answer:

<h3>Merits of modern periodic table:</h3>

The wrong position of some elements like argon, potassium, cobalt and nickel due to atomic weights have been solved by arranging the elements in the order of increasing atomic number without changing their own places.
The isotopes of some element have the same atomic numbers. Therefore, they find the same position in periodic table.
It separates metals from non-metals.
The groups of the table are divided into sub groups A and B due to their dissimilar properties which make the study of elements specific and easier.
The representative and transition elements have been separated.

Hope this helps...

Good luck on your assignment...

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3 years ago

Help asap <br> help show work <br> I need an A

MrRissso [65]

Answer: 17 (a) 360,000 ms 18 (a) 0.245 s

(b) 4.800 kg (b) 500 cm

(c) 560.0 dm (c) 68.00 m

(d) 72,000 mg (d) 0.025 Mg

<u>Explanation:</u>

Use the following table. Note the direction you are going to:

Right means move decimal to the right. Left means move decimal to the left.

$\boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}$

**********************************************************************************************

17(a) 360 s to ms o → → →o

$\boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}$

Move the decimal 3 places to the right --> 360_ _ _.

Fill in the blanks with zeroes --> 360,000

(b) 4800 g to kg o← ← ← o

$\boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}$

Move the decimal 3 places to the left --> 4.<u>8</u> <u>0</u> <u>0</u>

<u />

(c) 5600 dm to m o← o

$\boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}$

Move the decimal 1 place to the left --> 560. <u>0</u>

<u />

(d) 72 g to mg o → → →o

$\boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}$

Move the decimal 3 places to the right --> 72 _ _ _.

Fill in the blanks with zeroes --> 72,000

***********************************************************************************************

18 (a) 245 ms to s o← ← ← o

$\boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}$

Move the decimal 3 places to the left --> . <u>2</u> <u>4</u> <u>5</u>

(b) 5 m to cm o → →o

$\boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}$

Move the decimal 2 places to the right --> 5 _ _.

Fill in the blanks with zeroes --> 500

(c) 6800 cm to m o← ← o

$\boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}$

Move the decimal 2 places to the left --> 68. <u>0</u> <u>0 </u>

<u />

(d) 25 kg to Mg o← ← ← o

$\boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}$

Move the decimal 3 places to the left --> . _ 25

Fill in the blanks with zeroes --> .025

6 0

4 years ago

At high concentrations, inorganic fluoride inhibits enolase. In an anaerobic system that is metabolizing glucose as a substrate,

Alenkinab [10]

Answer:

<h2>A. 2-phosphoglycerate </h2>

Explanation:

Glycolysis is the process of breakdown of glucose into two 3-carbon molecules called pyruvate. The energy released during glycolysis is used to make ATP.

Enolase is the enzyme which plays very important role in glycolysis. In the 9th step of glycolysis, Enolase converts 2-phosphoglycerate into phosphoenolpyruvate.

This reaction of conversion of 2-phosphoglycerate to phosphoenolpyruvate is a reversible dehydration reaction.

Fluoride inhibits enolase, so when enolase is become non-functional then there is no convertion of 2-phosphoglycerate to phosphoenolpyruvate, so the concentraion of 2-phosphoglycerate is increases by the addition of fluoride.

5 0

3 years ago