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MA_775_DIABLO [31]
3 years ago
9

LAST ATTEMPT! Covalent compound naming !

Chemistry
1 answer:
GalinKa [24]3 years ago
5 0

Answer:sad

Explanation:

haaaaan   not

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4 years ago
What volume of a 0.240 m solution of barium nitrate is needed to prepare 0.500 l a  solution that is 0.0800 m in nitrate ion?
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Formula for Barium Nitrate = Ba(NO3)2

Thus based on stoichiometry:

1 mole of Ba(NO3)2 contains 2 moles of NO3-

Therefore, concentration of nitrate ion NO3- would be = 2*0.240 = 0.480 M

Use the relation:

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