The answer is 40
91+49=140
180-140=40
Answer:
P(X<118.81)=0.0803
Step-by-step explanation:
Assuming the distribution for the mean life is approximately normal, with mean 120 months and variance 64 months^2, we can calculate the parameters for a sampling distribution with sample size = 89 computers.
The sampling distribution mean will be equal to the mean for a single computer:

The standard deviation will be adjusted by the sample size as:

With these parameters, we can calculate the z-score for X=118.81.

Then, the probability that the mean of a sample of 89 computers is less than 118.81 months is:

You would put a Vinculum on top of it
Answer:
Option (4)
Step-by-step explanation:
Let x = ![\sqrt[4]{7}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B7%7D)
= (x)(x)(x)(x)
= 
= x⁴
Now we substitute the value x = ![\sqrt[4]{7}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B7%7D)
x⁴ = ![(\sqrt[4]{7})^4](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B7%7D%29%5E4)
x⁴ = 7
Therefore, Option (4) will be the answer.