Solve this system of equations by graphing. First graph the equations, and then type the solution. y=3x–2 y= – x+6 Click to sele
1 answer:
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Answer:
Z=±1.65
Step-by-step explanation:
Some previous concepts
The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.
A z-test for one mean "is a hypothesis test that attempts to make a claim about the population mean(μ)".
The null hypothesis attempts "to show that no variation exists between variables or that a single variable is no different than its mean"
The alternative hypothesis "is the hypothesis used in hypothesis testing that is contrary to the null hypothesis"
System of hypothesis
Null hypothesis:
Alternative hypothesis:
If the random variable is distributed like this:
The significance level provided is and the value of
.
Since we are conducting a bilateral test, then we have two critical values. We need to find two quantiles that accumulates 0.05 of the area on the tails of the normal standard distribution. And in order to find it we can use the following excel codes:
"=NORM.INV(0.05,0,1)" , "=NORM.INV(1-0.05,0,1)"
And we got this:
and
So the correct answer for this case is:
Z=±1.65
Answer:
Step-by-step explanation:
Hello!
You have the growth of 12 plants over a week (cm)
To construct a box plot you have to identify the 1st, 2nd, and 3rd Quartiles for the box and the maximum and minimum values for the whiskers.
Box
1st Quartile (Q₁)
Is the value of the data set that separates the bottom 25% from the top 75%. First, you need to calculate its position:
PosQ₁= n/4= 12/4= 3
So the first quartile is the third value.
6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14
Q₁= 7
2nd Quartile/ Median (Q₂/Me)
PosMe= 12/2= 6
The second quartile in the 6th value.
6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14
Q₂=Me= 8
3rd Quartile (Q₃)
PosQ₃= n*(3/4)= 12*(3/4)= 9
The third quartile is the 9th value.
6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14
Q₃= 10
The left whisker extends from the Q₁ to the minimum value.
The right whisker extends from the Q₃ to the maximum value.
Min= 6
Max= 14
'------| | |-------'
6 7 8 10 14
The box plot that best displays a summary of the data, is C.
I hope this helps!
